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3 years ago

PLEASE HELP !!! URGENT

Mathematics

2 answers:

balandron [24]3 years ago

8 0

Answer:

The answer is B--> 111 degrees

MA_775_DIABLO [31]3 years ago

6 0

Answer:

Here

X=75+36(Exterior angle of a triangle is equal to sum of interior opposite angle)

X=111

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Zinaida [17]

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4 years ago

A standard six-sided die was rolled a number of times, and the results were recorded in the table below. Use this information to

Maru [420]

Answer:

$P(Even) = 0.547$

Step-by-step explanation:

Given

$\begin{array}{ccccccc}{Sides} & {1} & {2} & {3} & {4} & {5} & {6} \ \\ {Freq} & {42} & {51} & {39} & {52} & {44} & {48} \ \end{array}$

Required

P(Even)

The even sides are: 2, 4, 6

So:

$P(Even) = P(2) + P(4) + P(6)$

This is then calculated as:

$P(Even) = \frac{n(2)}{Total} + \frac{n(4)}{Total} + \frac{n(6)}{Total}$

Replace n(2), n(4), n(6) with their frequencies

$P(Even) = \frac{51}{Total} + \frac{52}{Total} + \frac{48}{Total}$

The total frequency is:

$Total =42+51+39+52+44+48$

$Total =276$

So:

$P(Even) = \frac{51}{Total} + \frac{52}{Total} + \frac{48}{Total}$

$P(Even) = \frac{51}{276} + \frac{52}{276} + \frac{48}{276}$

Take LCM

$P(Even) = \frac{51+52+48}{276}$

$P(Even) = \frac{151}{276}$

$P(Even) = 0.547$ --- approximated

8 0

3 years ago

Hello can you please help me posted picture of question

yulyashka [42]

Total number of members = 12
Members to choose at a time = 2

This is a combination problem and we are to find the combination of 12 objects taken 2 at a time i.e. we are to find 12C2

12C2 = 66

So, there are 66 ways of selecting a president and vice president.

Therefore, the correct answer is option D

7 0

3 years ago

Use the fact that the world population was 2560 million in 1950 and 3040 million in 1960 to model the population of the world in

zimovet [89]

Answer:

The populaton in year 1991 will be of 5178.9 million of people

and the population in year 2020 will be of 8524.60 million of people

Step-by-step explanation:

We measure the time t in years and let t=0 in the year 1950.

We measure the population P(t) in millions of people, then P(0)=2560 and P(10) = 3040.

Since we are assuming that dp/dt=kP, this theorem gives the following.

$P(t) = P(0)e^{kt}= 2560e^{kt}$