8(2x-14)+13=4x-27
Use distribute property for the first one
16x-112+13=4x-27
16x-99=4x-27
12x=72
x=6. As a result, the value x is 6. Hope it help!
8y^2 + 6y + 1
List the factors of a and c.
a: 1 x 8, 2 x 4
c: 1 x 1
Since c is positive find factors from the list that will add up to the absolute value of b.
1, 1, 2, and 4 -----> (1 x 2) + (1 x 4) = 6
Arrange these four factors accordingly. Because both b and c are positive, both parentheses will have a plus sign.
( + )( + )
Ask yourself, "Which two factors with y as a variable will multiply to give me 8y^2?" Fill in the parentheses.
(4y + )(2y + )
Use trial and error(by FOILing).
(4y + 1)(2y + 1)
Check answer.
(4y)(2y) = 8y^2
(4y)(1) = 4y
(2y)(1) = 2y
(1)(1) = 1
Set up as a polynomial.
8y^2 + 4y + 2y + 1
Combine like-terms.
8y^2 + 6y + 1
So 8y^2 + 6y + 1 is equal to (4y + 1)(2y + 1).
<span>De opțiuni de răspuns pentru mine să aleg?</span>
<u>Answer:</u>
f(x) = (2x + 1)(2x − 1)
Explanation:
As we can see from the above function f(x) = 4 − 1, we need to find x-intercept, i.e., the value of x where this function's value is zero.
So let us Equate the function with zero
4 - 1 = 0 => 4 = 1 => = 1/4 => x =
Hence we get 2 values of x, i.e., +1/2, and -1/2.
So now we need to check out the functions which are zero at this values of x, so let us substitute values of x in each and every option and see the values of functions.
Option A - f(x) = (4x + 1)(4x − 1) = 3, -3
Option B - f(x) = (2x + 1)(2x − 1) = 0
Option C - f(x) = 4(x2 + 1) = 5
Option D - f(x) = 2(x2 − 1) = -3/2
Hence answer is Option B