Speed = Distance / time
Distance = Speed x time
In t hours, first plane travels = 600 t miles
In t hours, the second plane travels =150 t miles
After t hours the distance between the two planes is:
(600t+150t)= 750t ( since both travel in opposite directions)
When the distance is 900 miles:
750t= 900
Solve for t:
t= 900/750
t= 1.2 hours
After 1.2 hours.
1.2 x 60 = 72 minutes = 60 +12 = 1 hour and 12 minutes
Since both leave at 10 pm:
10am + 1 hour and 12 minutes : 11:12 am
They will be 900 miles apart at 11:12 am
Each one traveled:
Plane 1:
Distance: Speed x time = 600 mph x 1.2 = 720 miles
Plane 2:
Distance = Speed x time = 150 mph x 1.2 = 180 miles
Answer:
x2 - x - 12 = 0
Step-by-step explanation:
(x - 4) (x + 3) = 0
x(x + 3) -4(x + 3) = 0
x2 + 3x -4x - 12 = 0
x2 -x -12 = 0
The solution to the problem is as follows:
<span>cos2A - cos4A = -2 sin(6A/2).sin(-2A/2) = +2 sin(3A).sinA
and
sin4A - sin2A = 2 cos(6A/2).sin(2A/2) = 2 cos(3A).sinA
Hence RHS = (cos(2A)-cos(4A))/ (sin(4A)- Sin(2A)) = sin 3A / cos 3A = tan 3A = LHS
</span>
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You can add like terms. Like terms are terms that have the same variables and the same exponent.
11x + 5 + -11x + 29 =
= 11x + -11x + 5 + 29
= 34
Answer: 34
3:4 = 6:8 = 9:12 = 12:16 = 15:20 = 18:24
