3 years ago

PLEASE HELP simple geometry problem

Mathematics

1 answer:

vlabodo [156]3 years ago

5 0

Perimeter is adding the 3 sides together. Since both triangles have the same perimeter set both triangles to equal:

(x+3 + x+3 + x+3) = (x+3 + 2x-3 + x)

Simplify each side:

3x+9 = 4x

Subtract 3x from each side:

x=9

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Steve had 7 more than twice as many quarters as dimes. if the total value of her coins was $10.15, how many of each kind of coin

NemiM [27]

X=quarters, y=dimes
7+2x=y
0.25x+0.1y=10.15
we substitute the first equation into the second equation
0.25x+0.1(7+2x)=10.15
0.25x+0.7+0.2x=10.15
0.45x+0.7-0.7=10.15-0.7
0.45x=9.45
0.45x/0.45=9.45/0.45
x=21 quarters
7+2x=y, x=21
7+2(21)=y
7+42=y
y=49 dimes
check: 0.25x+0.1y=10.15 when x=21, y=49
21(0.25)=5.25 in quarters
49(0.1)=4.90 in dimes
5.25+4.90=10.15

3 0

3 years ago

Can someone help me with these problems? I'm in k12 and this assignment was in classkick, so if anyone already completed this an

Gemiola [76]

Answer:

See the explanation

Step-by-step explanation:

Given function

$Y=3x+1$

We need to find $y$ value corresponding to each $x$ value.

So, plug each $x$ value in equation we get,

$plug\ x=4\\y=3(4)+1\\y=12+1\\y=13\\\\plug\ x=6\\y=3(6)+1\\y=18+1\\y=19\\\\plug\ x=10\\y=3(10)+1\\y=30+1\\y=31$

Now in next part of question it ask us to check each ordered pair.

Let us plug each $x$ value and $y$ value in the function $y=-3x-5$

$plug\ (1,-8)\\-8=-3(1)-5\\-8=-3-5\\-8=-8\\\\plug(-5,0)\\0=-3(-5)-5\\0=15-5\\0\neq10\\\\plug\ (-2,1)\\1=-3(-2)-5\\1=6-5\\1=1\\\\plug\ (-1,-2)\\-2=-3(-1)-5\\-2=3-5\\-2=-2\\$