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2 years ago

21. Consider the diagram below.

Mathematics

2 answers:

VARVARA [1.3K]2 years ago

8 0

I’d say it’s either B or E not sure

Anna [14]2 years ago

7 0

Answer:

Step-by-step explanation:

the transversal across two parallel lines causes the consecutive internal angles to be congruent according to the consecutive internal angles theorem.

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The value V of a certain automobile that is t years old can be modeled by V(t) = 14,651(0.81). According to the model, when will

lakkis [162]

Answer:

a) The car will be worth $8000 after 2.9 years.

b) The car will be worth $6000 after 4.2 years.

c) The car will be worth $1000 after 12.7 years.

Step-by-step explanation:

The value of the car after t years is given by:

$V(t) = 14651(0.81)^{t}$

According to the model, when will the car be worth V(t)?

We have to find t for the given value of V(t). So

$V(t) = 14651(0.81)^{t}$

$(0.81)^t = \frac{V(t)}{14651}$

$\log{(0.81)^{t}} = \log{(\frac{V(t)}{14651})}$

$t\log{(0.81)} = \log{(\frac{V(t)}{14651})}$

$t = \frac{\log{(\frac{V(t)}{14651})}}{\log{0.81}}$

(a) $8000

V(t) = 8000

$t = \frac{\log{(\frac{8000}{14651})}}{\log{0.81}} = 2.9$

The car will be worth $8000 after 2.9 years.

(b) $6000

V(t) = 6000

$t = \frac{\log{(\frac{6000}{14651})}}{\log{0.81}} = 4.2$

The car will be worth $6000 after 4.2 years.

(c) $1000

V(t) = 1000

$t = \frac{\log{(\frac{1000}{14651})}}{\log{0.81}} = 12.7$

The car will be worth $1000 after 12.7 years.

5 0

2 years ago

Is 80 a multiple of 4

Gnoma [55]

No, 4 is a multiple of 80

5 0

2 years ago

A graphical depiction of a frequency distribution for numerical data in the form of a column chart is called a

Aloiza [94]

Answer:

A histogram

Step-by-step explanation:

Brainliest please

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2 years ago

100PT!<br> <img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B%202x%20%2By%5E%7B2%7D%20-%206y" id="TexFormula1" title="x^{2} + 2

Novay_Z [31]

x^2 + 2x + y^2 - 6y

5 0

3 years ago

Read 2 more answers

Please answer this mathematical problem.

n200080 [17]

x = total amount of gumballs

let's start subtracting the balls she's giving away

$\stackrel{total}{x}-\stackrel{\textit{to jaysen}}{\cfrac{x}{2}}\implies \stackrel{\textit{what's left}}{\cfrac{x}{2}}~\hfill \stackrel{\textit{half of what's left to Marinda}}{\cfrac{~~ \frac{x}{2}~~}{2}\implies \cfrac{x}{4}} \\\\\\ \stackrel{\textit{what was left minus Marinda's}}{\cfrac{x}{2}-\cfrac{x}{4}\implies \stackrel{\textit{what's left}}{\cfrac{x}{4}}}~\hfill ~\hfill \stackrel{\textit{a third of what's left to Zack}}{\cfrac{~~ \frac{x}{4}~~}{3}\implies \cfrac{x}{12}}$

$\stackrel{\textit{what was left minus Zack's}}{\cfrac{x}{4}-\cfrac{x}{12}\implies \stackrel{\textit{what's left}}{\cfrac{x}{6}}}~\hfill \stackrel{\textit{her sister gets 5 balls of what's left}}{ \cfrac{x}{6}-5 }$

and we also know that after all that has been subtracted, she's only left with 5, so we can say that

$\stackrel{\textit{what's finally left}}{\cfrac{x}{6}-5}~~ = ~~\stackrel{\textit{what's finally left}}{5}\implies \cfrac{x}{6}=10\implies \boxed{x = 60}$

5 0

2 years ago