At point of intersection the two equations are equal,
hence, 6x³ =6x²
6x³-6x²=0
6x²(x-1)=0 , the values of x are 0 and 1
The points of intersection are therefore, (0,0) and (1,6)
To find the slopes of the tangents at the points of intersection we find dy/dx
for curve 1, dy/dx=12x, and the other curve dy/dx=18x²
At x=0, dy/dx=12x =0, dy/dx=18x² = 0, hence the angle between the tangents is 0, because the tangents to the two curves have the same slope which is 0 and pass the same point (0,0) origin.
At x=1, dy/dx =12x = 12, dy/dx= 18x² =18, Hence the angle between the two tangents will be given by arctan 18 -arctan 12
= 86.8202 - 85.2364 ≈ 1.5838, because the slope of the lines is equal to tan α where α is the angle of inclination of the line.
Answer:
full chart below
Step-by-step explanation:
1x = 8 mi
2x = 10 mi
3x = 12 mi
4x = 14mi
5x = 16mi
Answer:
4 pi
Step-by-step explanation:
diameter = 2r
4 =2r
r =2
area = pi × (r)^2
= pi × 2^2
= 4 pi
Answer:
It’s d
Step-by-step explanation:
The table would be y = 6x
Divide the Y values by the X values and they all equal 6, so you multiply the X value by 6 to get y.
Look at the dots on the graph ( 1,5) (2,10) (3,15) (4,20)
Divide the Y value by the X and they all equal 5, soy = 5x
