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elena-s [515]
3 years ago
8

3) Solve the System of Equations using Elimination/Combinations. (5 points)

Mathematics
1 answer:
Schach [20]3 years ago
3 0

Answer:

(1, 2 )

Step-by-step explanation:

Given the 2 equations

- 2x - y = - 4 → (1)

x + 2y = 5 → (2)

Multiplying (2) by 2 and adding result to (1) will eliminate x- term

2x + 4y = 10 → (3)

Add (1) and (3) term by term to eliminate x

0 + 3y = 6

3y = 6 ( divide both sides by 3 )

y = 2

Substitute y = 2 into either of the 2 equations and solve for x

Substituting into (2)

x + 2(2) = 5

x + 4 = 5 ( subtract 4 from both sides )

x = 1

solution is (1, 2 )

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Plz help thank you thank you
natta225 [31]

Answer:

B

Only one that goes over once and up twice

6 0
3 years ago
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Elise put a magnet into a drawer. One-half of the items in the drawer stuck to the magnet. What fraction of the items in the dra
irinina [24]

Answer:

C.  

1/2

Step-by-step explanation:

To get the fraction of items that are not magnetic, subtract the fraction that stuck to the magnet (1/2) from 1 whole, or 2/2:

2/2 - 1/2 = 1/2

Thank you,I appreciate you asking this question

have a nice and relaxed day ! hope I helped .

3 0
3 years ago
(PLEASE HELP) The table below - does it represent an exponential function?
Aliun [14]
Short answer: I don't know, but that doesn't mean I can't give you something that you can decide for yourself.
y = 4*2^(2n - 2) is the pattern.
Go for broke. Try n = 4. You should get 256. Let's try it.
y = 4 * 2^(2*4 - 2)
y = 4 * 2^(8 - 2)
y = 4 * 2^6
y = 4 * 64
y = 256 yup it works.

The other end is just as important. Suppose n = 1
Then y = 4 * 2^(2*1 - 2) = 4 * 2^0 = 4*1 = 4 Both work.

If this formula is correct, we can abbreviate it to make your task easier.
y = 4 * 2^(2n - 2)
y = 2^2 * 2^(2n - 2)
y = 2^(2n - 2 + 2)
y = 2^(2n) Now try the two end points again.

n = 4
y = 2^(2*4)
y  =  2^8
y = 256

n = 1
y = 2^(2*1)
y = 2^2
y = 4 which again checks.

so y = 2^(2n) I think is an exponential function.
Sorry my explanation is so long.

6 0
4 years ago
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tangare [24]
I’m pretty sure it’s false
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3 years ago
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Draw a graph of the rose curve.<br><br> r = 4 cos 2θ, 0 ≤ θ ≤ 2π
alukav5142 [94]
See the attachment below gor graph
hope that helps 

3 0
3 years ago
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