For an initial amount deposited P and an annual interest rate r, the total amount T in the account after t years is given by:
For P = $2200, r = 7% and t = 5 years, we have:
Answer:
Table A and Graph A
Step-by-step explanation:
See the attached tables and graphs.
Table A gives the ordered pairs (1,2), (2,4) and (3,6).
Take the first two pairs of points.
The equation of the straight line passing through those points will be
⇒ y = 2x
Therefore, the table A represents the equation y= 2x.
Now, as shown in graph A, the points (0,0) and (1,2) and (2,4) through which this equation of straight line passes.
Therefore, the equation y = 2x is represented by graph A.
Hence, Table A and Graph A are the answers.
Answer:
Im not sure what type of solution you are looking for. You should be more specific. Though I will still give you some helpful solutions and you use the one you need.
Step-by-step explanation:
Factored: y=168x+67y-49
Solved for Y; -28x/11 + 49/66
Solved for X: -11y/28 + 7/24
X and Y intercepts:
X=( 7/24, 0 )
Y= ( 0, 49/66 )
I hope these answers help. Next time be more specific to what your looking for and make sure your equation is written correctly.
The easy part is isolating the absolute-value term:
5 + 7 |2<em>x</em> - 1| = -44
7 |2<em>x</em> - 1| = -49
|2<em>x</em> - 1| = -7
Remember that the absolute value function returns a positive number that you can think of as the "size" of that number, or the positive distance between that number and zero. If <em>x</em> is a positive number, its absolute value is the same number, |<em>x</em>| = <em>x</em>. But if <em>x</em> is negative, then the absolute value returns its negative, |<em>x</em>| = -<em>x</em>, which makes it positive. (If <em>x</em> = 0, you can use either result, since -0 is still 0.)
The important thing to take from this is that there are 2 cases to consider: is the expression in the absolute value positive, or is it negative?
• If 2<em>x</em> - 1 > 0, then |2<em>x</em> - 1| = 2<em>x</em> - 1. Then the equation becomes
2<em>x</em> - 1 = -7
2<em>x</em> = -6
<em>x</em> = -3
• If 2<em>x</em> - 1 < 0, then |2<em>x</em> - 1| = - (2<em>x</em> - 1) = 1 - 2<em>x</em>. Then
1 - 2<em>x</em> = -7
-2<em>x</em> = -8
<em>x</em> = 4
