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astraxan [27]
3 years ago
7

2.2 The following data show the distances (in miles) from the homes of off-campus statistics students to the college. Create a s

tem plot using the data and identify any outliers: 0.5; 0.7; 1.1; 1.2; 1.2; 1.3; 1.3; 1.5; 1.5; 1.7; 1.7; 1.8; 1.9; 2.0; 2.2; 2.5; 2.6; 2.8; 2.8; 2.8; 3.5; 3.8; 4.4; 4.8; 4.9; 5.2; 5.5; 5.7; 5.8; 8.0
Mathematics
1 answer:
Liula [17]3 years ago
8 0

Answer:

Step-by-step explanation:

From the given set of data,

Stem-leaf plot will be,

Stem                Leaf

  0                    5 7

  1                     1 2 2 3 3 5 5 7 7 8 9  

  2                    0 2 5 6 8 8 8

  3                    5 8

  4                    4 8 9

  5                    2 5 7 8

  6

  7

  8                    0

Key for the given stem and leaf plot → 0 |  5 = 0.5

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Write the value of the expression 2^3/2^3
kiruha [24]

Answer:

1

Step-by-step explanation:

\frac{2^3}{2^3}\\\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}\\=2^{3-3}\\2^{3-3}=1\\2^{3-3}\\\mathrm{Subtract\:the\:numbers:}\:3-3=0\\=2^0\\\mathrm{Apply\:rule}\:a^0=1,\:a\ne \:0\\=1

6 0
3 years ago
Write an equation for the circle with endpoints of a diameter (9, 4) and (-3, -2)
inysia [295]
If the diameter is at (9,4) and (-3,-2), then the center of the circle is the midpoint of that segment.

and since we know that the radius of a circle is half of the diameter, whatever long that diameter segment is, the radius is half that.

\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ 9 &,& 4~) 
%  (c,d)
&&(~ -3 &,& -2~)
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)
\\\\\\
\left( \cfrac{-3+9}{2}~~,~~\cfrac{-2+4}{2} \right)\implies \stackrel{center}{(3~,~1)}

\bf -------------------------------\\\\
~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ 9 &,& 4~) 
%  (c,d)
&&(~ -3 &,& -2~)
\end{array}
\\\\\\
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
d=\sqrt{(-3-9)^2+(-2-4)^2}\implies d=\sqrt{(-12)^2+(-6)^2}
\\\\\\
d=\sqrt{180}\qquad \qquad \qquad radius=\cfrac{\sqrt{180}}{2}

\bf -------------------------------\\\\
\textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{3}{ h},\stackrel{1}{ k})\qquad \qquad 
radius=\stackrel{\frac{\sqrt{180}}{2}}{ r}
\\\\\\
(x-3)^2+(y-1)^2=\left( \frac{\sqrt{180}}{2} \right)^2\implies (x-3)^2+(y-1)^2=\cfrac{(\sqrt{180})^2}{2^2}
\\\\\\
(x-3)^2+(y-1)^2=\cfrac{180}{4}\implies (x-3)^2+(y-1)^2=45
7 0
3 years ago
Which is not an equation of the line going through (6, 7) and (2, –1)?
garri49 [273]
Answer - D.

you basically find the equation of the line first and eliminate the wrong answers...

Strategy:  before u do any of this, label your coordinates as (X1,Y1) and (X2,Y2) and u can choose any of ur points to be as x1 or x2 or y1 or y1...
basically, I'll choose (6,7) as (x1,y1) and (2,-1) as (x2,y2). SO,

First you have to  find the gradient (m) of the line.
  you do this by using the formula m = Y2-Y1 / X2-X1 (where '/' is division sign) ....
Put the numbers in their respective places and your gradient will be 2x. we put the x after our number to represent it as a gradient as the straight line formula is y = mx+c and you've found the m.
NOW.
use the formula Y-Y1=m(x-x1) to find the equation of the line.Again u can use any Y1 and X1 here but remember your m is 2

replace the digits and solve...Hopefully you'll get sth like this if you use the points (6,7):
Y-7 = 2(x-6) ....
y=2x-12+7...
Y=2x-5! <<<< this is your straight line equation!
Now all u gotta do is rearrange all your options into y = mx+c.
D. is incorrect as it gives us y=2x+5 and not y = 2x-5 unlike the others 
 

Hope you get it!




7 0
3 years ago
HELP it’s not 20.40 which is what someone else answered lol
kvv77 [185]

Answer:

I think it 19.6

Step-by-step explanation:

Sorry if im wrong

7 0
3 years ago
Help pls it’s due today *photo*
a_sh-v [17]

9514 1404 393

Answer:

   ACBD-BDAC

Step-by-step explanation:

It is convenient to compare the values of each of the functions when h=1. On the graphs, find 1 on the horizontal axis, then read the value of the function at that point from the vertical axis.

For the equations, the value for h=1 will be its coefficient in the equation.

__

1) a: 80,b: 50, c: 75, d: 30

Fastest to slowest is ACBD.

__

2) a: 4, b: 2, c: 8, d: 3

Slowest to fastest is BDAC

__

The code is these lists, separated by a dash: ACBD-BDAC.

4 0
3 years ago
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