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Nat2105 [25]
3 years ago
9

How do the average rates of change for the functions f(x) = 2x2 and g(x) = 3x2 over the interval −3 ≤ x ≤ 4 compare?

Mathematics
1 answer:
DedPeter [7]3 years ago
3 0
<h2>Answer with explanation:</h2>

The average rate of change for function f(x) over the interval a ≤ x ≤ b is given by :-

\dfrac{f(b)-f(a)}{b-a}

So, the rate of change for function f(x)=2x^2  over the interval −3 ≤ x ≤ 4 :

=\dfrac{2(4)^2-2(-3)^2}{4-(-3)}=\dfrac{14}{7}=2

The rate of change for function g(x)=3x^2  over the interval −3 ≤ x ≤ 4 :

=\dfrac{3(4)^2-3(-3)^2}{4-(-3)}=\dfrac{21}{7}=3

So, the rate of change for  g(x) is greater than f(x) over the interval −3 ≤ x ≤ 4.

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Step-by-step explanation:

In this case, you need to remember that:

1. Tthe word "less than" indicates a subtraction.

2.  By definition, the "Difference" in the result of a subtraction.

3. The word "times" indicates multiplication,

Based on the information given above, you know that  " Six times the difference of a number and five" can be expressed as:

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Now you can substitute n=9 into the expression and the evaluate in order to find the value of the expression. This is:

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