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vladimir2022 [97]
2 years ago
11

A function is represented by the values in the table.

Mathematics
2 answers:
dimulka [17.4K]2 years ago
7 0

Answer:

Is

Step-by-step explanation:

I took the quiz

Pavel [41]2 years ago
6 0

Answer:

is

Step-by-step explanation:

took the quiz

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Could some please help and explain?
Sophie [7]

Answer:

x = 7

Step-by-step explanation:

A rhombus is a parallelogram where all sides are equal. Therefore, as we know two sides are equal to 7x+8 and 9x-6, we can say that

7x+8 = 9x - 6

subtract 7x from both sides to put the variable on one side

2x - 6 = 8

add 6 to both sides to isolate the variable and its coefficient

2x = 14

divide both sides by 2 to isolate x

x = 7

7 0
2 years ago
Justin surveyed 280 of the students in his school about their favorite color. 98
Mamont248 [21]

Answer:

\frac{98}{280}  \times  \frac{100}{1}

0.35 \times 100 \\  = 35\%

8 0
3 years ago
Solve for x.<br> -5x + 12x - 8x = -24<br> x = _________a0
hichkok12 [17]

Answer:

x=24

Step-by-step explanation:

-5x+12x-8x=-24

Add like terms

12x-13x=-24

-x=-24

divide by 1

x=24

5 0
3 years ago
A coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces. A random sample of 15 co
Luda [366]

Answer:

We conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

Step-by-step explanation:

We are given that a coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces.

A random sample of 15 containers were weighed and the mean weight was 31.8 ounces with a sample standard deviation of 0.48 ounces.

Let \mu = <u><em>mean weight of coffee in its containers.</em></u>

SO, Null Hypothesis, H_0 : \mu \geq 32 ounces     {means that the mean weight of coffee in its containers is at least 32 ounces}

Alternate Hypothesis, H_A : \mu < 32 ounces      {means that the mean weight of coffee in its containers is less than 32 ounces}

The test statistics that would be used here <u>One-sample t-test statistics</u> as we don't know about population standard deviation;

                             T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean weight = 31.8 ounces

             s = sample standard deviation = 0.48 ounces

             n = sample of containers = 15

So, <u><em>the test statistics</em></u>  =  \frac{31.8 -32}{\frac{0.48}{\sqrt{15} } }  ~ t_1_4  

                                      =  -1.614

The value of t test statistics is -1.614.

<u>Now, at 0.01 significance level the t table gives critical value of -2.624 at 14 degree of freedom for left-tailed test.</u>

Since our test statistic is more than the critical value of t as -1.614 > -2.624, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u><em>we fail to reject our null hypothesis</em></u>.

Therefore, we conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

8 0
3 years ago
14.1-191<br> Is this the answer?
enyata [817]
I don’t know if this is what you’re asking but 14.1-191 = -176.9
4 0
2 years ago
Read 2 more answers
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