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pishuonlain [190]
3 years ago
14

If 12+ blank=0+12, than blank must equal

Mathematics
2 answers:
Pachacha [2.7K]3 years ago
7 0
Blank would have to equal zero
IrinaK [193]3 years ago
4 0
0. 12+0=0+12 blank is 0.
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Alex, Bob, and Cole have a combined weight of 111 kilograms. If Alex weighs 44 kg, and Bob weighs three-forth of Alex's weight,
vlabodo [156]

Answer:34

Step-by-step explanation:

Weight of Alex:44

Weight of Bob:44*(3/4)

=33

Combined weight of all of them:111

Combined weight of Alex and Bob=44+33=77

Cole's weight=111-77 =34

8 0
3 years ago
13f + 6 -f = -3 <br><br> help?
malfutka [58]

Answer:

f = -3/4

Step-by-step explanation:

13f + 6 -f = -3

Combine like terms

12f +6 = -3

Subtract 6 from each side

12f+6-6 = -3-6

12f = -9

Divide each side by 12

12f/12 = -9/12

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Question: (Graph attached below)
antoniya [11.8K]

16 I just know that it's 16 GL to ya

6 0
3 years ago
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Find gradient <br><br>xe^y + 4 ln y = x² at (1, 1)​
cricket20 [7]

xe^y+4\ln y=x^2

Differentiate both sides with respect to <em>x</em>, assuming <em>y</em> = <em>y</em>(<em>x</em>).

\dfrac{\mathrm d(xe^y+4\ln y)}{\mathrm dx}=\dfrac{\mathrm d(x^2)}{\mathrm dx}

\dfrac{\mathrm d(xe^y)}{\mathrm dx}+\dfrac{\mathrm d(4\ln y)}{\mathrm dx}=2x

\dfrac{\mathrm d(x)}{\mathrm dx}e^y+x\dfrac{\mathrm d(e^y)}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x

e^y+xe^y\dfrac{\mathrm dy}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x

Solve for d<em>y</em>/d<em>x</em> :

e^y+\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x

\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x-e^y

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x-e^y}{xe^y+\frac4y}

If <em>y</em> ≠ 0, we can write

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2xy-ye^y}{xye^y+4}

At the point (1, 1), the derivative is

\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=1,y=1}=\boxed{\dfrac{2-e}{e+4}}

4 0
3 years ago
Peter has four horses. Each one eats 4 pounds of oats, twice a day. How many pounds of oats does he need to feed his horses for
Fiesta28 [93]
4 poundsx2times per day= 8 pounds
8 pounds x 4 horses=32 pounds
32 poundsx 3 days = 96 pounds
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3 years ago
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