Answer:
second
Step-by-step explanation:
the second one which is B
7/2
Don't awnser the bots
They will try ro scam you
![2(x-2)^2=8(7+y)\\2(x-2)^2=56+8y \Rightarrow y={1\over{8}}[2(x-2)^2-56]={1\over{4}}(x-2)^2-7\\finally\\y={1\over{4}}(x-2)^2-7\\let ~change~x~and~y\\x={1\over{4}}(y-2)^2-7\\x+7={1\over{4}}(y-2)^2\\4(x+7)=(y-2)^2\\y-2=\pm\sqrt{4(x+7)}\\\\y=2\pm\sqrt{4x+28}](https://tex.z-dn.net/?f=2%28x-2%29%5E2%3D8%287%2By%29%5C%5C2%28x-2%29%5E2%3D56%2B8y%20%5CRightarrow%20y%3D%7B1%5Cover%7B8%7D%7D%5B2%28x-2%29%5E2-56%5D%3D%7B1%5Cover%7B4%7D%7D%28x-2%29%5E2-7%5C%5Cfinally%5C%5Cy%3D%7B1%5Cover%7B4%7D%7D%28x-2%29%5E2-7%5C%5Clet%20~change~x~and~y%5C%5Cx%3D%7B1%5Cover%7B4%7D%7D%28y-2%29%5E2-7%5C%5Cx%2B7%3D%7B1%5Cover%7B4%7D%7D%28y-2%29%5E2%5C%5C4%28x%2B7%29%3D%28y-2%29%5E2%5C%5Cy-2%3D%5Cpm%5Csqrt%7B4%28x%2B7%29%7D%5C%5C%5C%5Cy%3D2%5Cpm%5Csqrt%7B4x%2B28%7D)
