All categories

4 years ago

23. A 340 million square mile forest is how many hectares?

Mathematics

1 answer:

e-lub [12.9K]4 years ago

5 0

Answer: in 340 million square miles there are 8.808 x 10^10 hectares

Step-by-step explanation:

You might be interested in

Please help. Find the product or quotient in simplified form. Explain how to multiply and divide fractions.

miskamm [114]

<span>5 1/6 x 1/3
</span>first convert 5 1/6 (which is a mixed fraction) into an improper fraction ...
=> 6*5+1/6 = 31/6
=>now we have ... 31/6 * 1/3
=> to multiply fractions we multiply the numerators ( top numbers ) with each other and the denominators (bottom numbers ) also the same way ...
=> 31/6 * 1/3 => 31*1 / 6*3 => 31/18
=> then divide them to get answer as mixed fraction ..
=> 1 13/18 ..

<span>3 1/2 / 1 1/3
</span>=> here also first convert 3 1/2 and 1 1/3 into improper fractions ..
=> 3 1/2 => 2*3+1/2 => 7/2
=> 1 1/3 => 3*1+1/3=> 4/3
=> now divide them ..
=> 7/2/4/3
=> for dividing fractions we take the reciprocal of one fraction and then multiply ..
=> 7/2 * 3/4
=> now multiply these two fractions ..
=> 7*3/2*4 => 21/8
=> answer as mixed fraction = 2 5/8 ...

Hope it helps !!!

7 0

3 years ago

Compute the differential of surface area for the surface S described by the given parametrization.

AysviL [449]

With $S$ parameterized by

$\vec r(u,v)=\langle e^u\cos v,e^u\sin v,uv\rangle$

the surface element $\mathrm dS$ is

$\mathrm dS=\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

We have

$\dfrac{\partial\vec r}{\partial u}=\langle e^u\cos v,e^u\sin v,v\rangle$

$\dfrac{\partial\vec r}{\partial v}=\langle -e^u\sin v,e^u\cos v,u\rangle$

with cross product

$\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\langle ue^u\sin v-ve^u\cos v,-ve^u\sin v-ue^u\cos v,e^{2u}\cos^2v+e^{2u}\sin^2v\rangle$

$\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\langle e^u(u\sin v-v\cos v),-e^u(v\sin v+u\cos v),e^{2u}\rangle$

with magnitude

$\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{e^{2u}(u\sin v-v\cos v)^2+e^{2u}(v\sin v+u\cos v)^2+e^{4u}}$

$\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=e^u\sqrt{u^2+v^2+e^{2u}}$

So we have

$\mathrm dS=\boxed{e^u\sqrt{u^2+v^2+e^{2u}}\,\mathrm du\,\mathrm dv}$

8 0

3 years ago

A diver starts out at 338 feet below the surface. She then swims upward 102 feet. Use a signed number to represent the diver's c

BigorU [14]

I want to sing but i want to sing and i can't sing because i want to sing but i sing

5 0

3 years ago

Graph the six terms of a finite sequence where a1 = −6.25 and r = 1.25.

Virty [35]

Answer:

Step-by-step explanation:

As per the question statement, a₁ is -6.25 and common ratio (r) is 1.25.

Therefore, the six terms of finite sequence would be as per the following equation $f(n) = a1(r)^{n-1}$ . Thus, the series would be

a1 = -6.25
a2 = -6.25*r = -6.25*(1.25) = -7.8125
a3 = -6.25*r^2 = -6.25*(1.25)^2 = -9.765625
a4 = -6.25*r^3 = -6.25*(1.25)^3 = -12.20703125
a5 = -6.25*r^4 = -6.25*(1.25)^4 = -15.2587890625
a6 = -6.25*r^5 = -6.25*(1.25)^5 = -19.073486328125

So the points on the graph will be on following points,

(1, -6.25), (2, -7.8125), (3, -9.765625), (4, -12.20703125), (5, -15.2587890625), (6, -19.073486328125).

The graph would look like as attached.

3 0

3 years ago

Need help figuring this equation 1/12c =.6

soldi70 [24.7K]

1/12c = 0.6

To remove a fraction you simply multiply it by its inverse fraction (take the original fraction and flip it! So, multiply it by 12/1 (which is the same as saying 12).

12(1/12c) = 0.6*12

The 12 cancels out leaving this:

c = 0.6 * 12
c = 7.2

If you don't have or are allowed to use a calculator. To compute that you simply make 0.6 into a fraction then multiply the numerator by 12. .6 is in the tenths place so you can write it like this:
6/10 simplifying it becomes, 3/5

3/5 * 12 = 36/5

Now! That was assuming 1/12c was written like this:
(1/12)c = 0.6

If it was actually written like this:
1/(12c) = 0.6 then you'll do this.

Multiply 0.6 by 12c. Which will get you 7.2c. After that you need to get c alone, so you divide both sides by 7.2. Yielding the result:

1/7.2 = c

c = 0.1389...

5 0

3 years ago