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olya-2409 [2.1K]
4 years ago
12

Need these also any help

Mathematics
2 answers:
AnnyKZ [126]4 years ago
7 0
<h3>Answers:</h3>
  1. b
  2. a
  3. d
  4. c

==============================

Explanation:

For problem 1, we will plot a closed circle at x = -2 to include this value in the shaded solution set. We include it because of the "or equal to". The shading is to the right because of the "greater than". So we're describing all x values that are either equal to -2 or larger than -2. You could say "x is -2 or larger".

---------------------

In problem 2, we'll exclude the endpoint since we don't have "or equal to". We shade to the left to visually show all values smaller than 3.

---------------------

In problem 3, we follow the same idea as the last problem. We have an open hole to exclude the endpoint and shade to the right of 12 to describe all values larger than 12.

---------------------

With problem 4, we now include the endpoint again. This is similar to problem 1. We shade to the left to describe x values that are either -15 or smaller.

Irina18 [472]4 years ago
3 0
B, d, c, a i've done this and got them right
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<u>Given</u>:

Given that the function p(x)=\left\{\begin{array}{ll}\frac{1}{4} x^{2}+1 & \text { if } x \leq 3 \\\frac{1}{4} x+2.5 & \text { if } x>3\end{array}\right.

We need to determine the function to evaluate when x = -5.

<u>Function</u>:

The function is given two interval. The interval x\leq 3 means that x takes all values less than or equal to 3.

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Thus, Option A is the correct answer.

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