The minimum surface area that such a box can have is 380 square
<h3>How to determine the minimum surface area such a box can have?</h3>
Represent the base length with x and the bwith h.
So, the volume is
V = x^2h
This gives
x^2h = 500
Make h the subject
h = 500/x^2
The surface area is
S = 2(x^2 + 2xh)
Expand
S = 2x^2 + 4xh
Substitute h = 500/x^2
S = 2x^2 + 4x * 500/x^2
Evaluate
S = 2x^2 + 2000/x
Differentiate
S' = 4x - 2000/x^2
Set the equation to 0
4x - 2000/x^2 = 0
Multiply through by x^2
4x^3 - 2000 = 0
This gives
4x^3= 2000
Divide by 4
x^3 = 500
Take the cube root
x = 7.94
Substitute x = 7.94 in S = 2x^2 + 2000/x
S = 2 * 7.94^2 + 2000/7.94
Evaluate
S = 380
Hence, the minimum surface area that such a box can have is 380 square
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Answer:
The answer to this problem is x equals 14
Step-by-step explanation:
The answer is zero.
Explanation:
The 4 is in the ten-thousands place.
Write the number 47,283 with an additional zero in the 100,000 place.
047,283
To round to the nearest 100,000, all digits to the right of the 100,000 place become zero. That means that the digits 47283 all become zero. Since 4 is less than 5, the digit to its left is not raised by 1, so the 100,000 place digit remains zero, and you end up with 000,000, which is simply 0.
Answer: 0

252,333.258656 inches 2
I think something is wrong here
Answer:
Their is 10% of males and females.
Step-by-step explanation:
Because if you subtract 50% and 40%you would get 10% that means their is more females.