Question

a survey of lobster fishermen found that they catch an average of 32 pounds of lobster per day with a standard deviation of 4 pounds. if a random sample of 36 lobster fishermen is selected, what is the possibility that their average catch is less than 31.5 pounds? assume the distribution of weights of lobster is normal

Answer 1

There is a probability of 22.66% that their average catch is less than 31.5 pounds

What is z score?

The z score is used to determine by how many standard deviations the raw score is above or belaw the mean. It is given by:

z = (raw score  - mean)/ (standard deviation ÷ √sample)

Given that, mean = 32, std = 4, sample = 36, hence:

For 31.5:

z = (31.5 - 32) / (4 ÷√36) = -0.75

P(z < -0.75) = 0.2266

There is a probability of 22.66% that their average catch is less than 31.5 pounds

Find out more on z score at: brainly.com/question/25638875