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3 years ago

Find the area of the blue shaded region.

Mathematics

1 answer:

Elodia [21]3 years ago

4 0

Answer:

Step-by-step explanation:

area of whole figure=

l×b

=20×10

=200

also,area of small fig.

=l×b

=18×8

=144

thus area of shaded part =a of whole- a of small

=200-144

=56

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Suppose you were given $800 from your uncle. You deposited that money in a bank and added $55 per month. Write an algebraic expr

gogolik [260]

800+55x

hope this helps

7 0

3 years ago

What is the value of x?

blsea [12.9K]

Since these are supplementary angles (two angles which sum to 180°) we can say:

4x+x=180 combine like terms on left side

5x=180 divide both sides by 5

x=36°

3 0

3 years ago

Can someone help me write the equations and solve, please.

Novay_Z [31]

Answer:

Number 11: She has to add 5/36 of a cup

Number 12: The present costs $22,2

Number 13: 56,7 pounds is the weight of the package.

Number 14: You started with 40 muffins

Step-by-step explanation:

Number 11: 1/4 = 9/36 and 1/9 = 4/36

3*1/4 - 3*1/9 = 3*9/36 - 3*4/36 = 5/36

Number 12: 13,32/x= 3/5 ( or 0,6)

x = 13,32/0,6 = 22,2

Number 13: x * 5/7 = 40,5

x = 40,5/ (5/7) or 40,5 * 7/5 = 283,5/5 = 56,7

Number 14: 12/x = 3/10 (or 0,30)

x= 12/0,30 = 40

6 0

3 years ago

If a=under root s(s-a)(s-b)(s-c) then the value of a, when a =3 b =4c = 5 and s =a+b+c by 2

kramer

Answer:

Step-by-step explanation:

Here it's given that ,

$\sf\red{\longrightarrow} A=\sqrt{s(s-a)(s-b)(s-c)}$

Also ,

$\sf\red{\longrightarrow} s =\dfrac{a+b+c}{2}$

And we need to find out the value of A , when

a = 3
b = 4
c = 5

So , on substituting the respective values to find s we have ,

$\sf\red{\longrightarrow} s =\dfrac{3+4+5}{2}=\dfrac{12}{2}=\bf{6}$

Now let's find out A as ,

$\sf\red{\longrightarrow} A = \sqrt{6(6-3)(6-4)(6-5)} \\$

$\sf\red{\longrightarrow}A =\sqrt{6 * 3 * 2 * 1}\\$

$\sf\red{\longrightarrow} A = \sqrt{3^2 * 2^2 *1^2}\\$

$\sf\red{\longrightarrow}A = 3*2\\$

$\sf\red{\longrightarrow}\boxed{\qquad \blue{\bf A = 6 \qquad}}$

7 0

2 years ago

Use distributive property to simplify. 10(-8s-k) just need to check if -80s-10k is correct.

Nitella [24]

10(-8s-k)
(10) (-8s + -k)
(10) (-8s) + (10) (-k)
= -80s - 10k
= -10k-80s

6 0

3 years ago