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3 years ago

Did I do anything wrong? how would I solve it if I did do something wrong??

Mathematics

2 answers:

s344n2d4d5 [400]3 years ago

5 0

Thats right!well done

levacccp [35]3 years ago

3 0

Answer:

No its correct x=25

Step-by-step explanation:

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Anyone know the answer??

Xelga [282]

Answer

$3.5 x 10^{3}$

Step-by-step explanation

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3 years ago

Label each of the triangles illustrated below

AVprozaik [17]

A: Equilateral
B: Obtuse
C: Obtuse
D: Right
E: Obtuse
F: Acute

8 0

3 years ago

Name two solutions for each inequality.

ahrayia [7]

So,

#1: $n \geq 3 \frac{11}{16} + 4 \frac{1}{2}$

Convert to like improper fractions.
$n \geq \frac{59}{16} + \frac{72}{16}$

Add.
$n \geq \frac{131}{16}\ or\ 8 \frac{3}{16}$

So, one solution could be $8 \frac{3}{16}$ .

Another solution could by 9. There is also 10, 11, 12, etc., and all numbers in between.

#2: $k \ \textless \ 6 \frac{2}{5} * 15$

Convert into improper fraction form.
$k \ \textless \ \frac{32}{5} * 15$

Multiply.
$\frac{(2^5)(3)(5)}{5}$

Cross-cancel, and we have our final result.
$(2^5)(3) = 96$
k < 96

96 is not a solution.

95 is a solution.

So is 94, 93, 92, etc, and all numbers in between.

6 0

3 years ago

Differential cos^2x dy/dx =e^y-tanx

gulaghasi [49]

Answer:

y=t−1+ce

−t

where t=tanx.

Given, cos

+y=tanx

⇒

+ysec

x=tanxsec

x ....(1)

Here P=sec

x⇒∫PdP=∫sec

xdx=tanx

∴I.F.=e

tanx

Multiplying (1) by I.F. we get

tanx

ysec

x=e

tanx

tanxsec

Integrating both sides, we get

tanx

=∫e

tanx

.tanxsec

xdx

Put tanx=t⇒sec

xdx=dt

∴ye

=∫te

dt=e

(t−1)+c

⇒y=t−1+ce

−t

where t=tanx

8 0

2 years ago

Which function has the largest slope?

photoshop1234 [79]

C as you know what you’re going through to your point of what time you’re leaving the school you

4 0

3 years ago

Read 2 more answers

Did I do anything wrong? how would I solve it if I did do something wrong??​

Did I do anything wrong? how would I solve it if I did do something wrong??