The tension on each segment of the clothesline is : 110 N
<u>Given data : </u>
mass of object = 100 n = 10 kg
Horizontal distance of clothesline = 4 m
middle of clothesline sag s by : 1m
<h3 /><h3>Determine the tension on each segment of clothesline</h3>
<u>First step</u> : calculate the horizontal angle made by the sagging
β = arctan ( 1 m / 2m ) ----- ( 1 )
= arctan ( 0.5 )
≈ 26.57°
Note : Tension in th y axis ( Ty ) = Tsinβ
Therefore :
Tension on each segment can be calculated using the formula below
2Tsinβ - mg = 0
solve for T
T = mg / 2sinβ
= ( 10 * 9.8 ) / 2 * sin 26.57°
= 98 / 0.89
= 110 N
Hence we can conclude that the tension on each segment of the clothesline is : 110 N
Learn more about Tension calculations : brainly.com/question/24994188
3x = 3 x 6 should be the equation because 3 x x is 3 x 6
Answer:
A 2:10 kg wooden block is tied to a rope and spun in a circular path of radius 1.12m. The block obteins a maximum speed of 10m/s
Explanation:
Answer:
"The pen is mightier than the sword" is a saying that many people learn as children. Of course, it means that ideas that are expressed in writing can be much more consequential than violence. Words can influence and inspire countless people, and they can live on indefinitely.
Explanation:
