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il63 [147K]
3 years ago
9

PLZ HELP WILL GIVE 50 POINTS - QUADRATIC APPLICATIONS

Mathematics
1 answer:
Contact [7]3 years ago
6 0

Answer:

The bird will be at a ground distance of 10.04 units away.

Step-by-step explanation:

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

f(x) = ax^{2} + bx + c

It's vertex is the point (x_{v}, y_{v})

In which

x_{v} = -\frac{b}{2a}

y_{v} = -\frac{\Delta}{4a}

Where

\Delta = b^2-4ac

If a<0, the vertex is a maximum point, that is, the maximum value happens at x_{v}, and it's value is y_{v}.

Equation for the height:

The height of the bird after x seconds is given by:

h(x) = -0.114x^2 + 2.29x + 3.5

Which is a quadratic equation with a = -0.114, b = 2.29, c = 3.5.

When the bird is at its highest?

Quadratic equation with a < 0, and thus, at the vertex. The ground distance is the x-value of the vertex. Thus

x_{v} = -\frac{b}{2a} = -\frac{2.29}{2(-0.114)} = 10.04

The bird will be at a ground distance of 10.04 units away.

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x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Step-by-step explanation:

We need to solve the equation \frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1} and find values of x.

Solving:

Find the LCM of denominators x-1,x and x-1. The LCM is x(x-1)

Multiply the entire equation with x(x-1)

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The values of x are x=1 and x=2

Checking for extraneous roots:

Extraneous roots: The root that is the solution of the equation but when we put it in the equation the answer turns out not to be right.

If we put x=1 in the equation, \frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}  the denominator becomes zero i.e

\frac{1}{1-1}+\frac{2}{1}=\frac{1}{1-1}\\\frac{1}{0}+2=\frac{1}{0}

which is not correct as in fraction anything divided by zero is undefined. So, x=1 is an extraneous solution.

If we put x=2  in the equation,

\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}

\frac{1}{2-1}+\frac{2}{2}=\frac{2}{2-1}\\\frac{1}{1}+1=\frac{2}{1}\\1+1=2\\2=2

So, x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Keywords: Solving Equations and checking extraneous solution

Learn more about Solving Equations and checking extraneous solution at:

  • brainly.com/question/1626495
  • brainly.com/question/2959656
  • brainly.com/question/2456302

#learnwithBrainly

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