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il63 [147K]
3 years ago
9

PLZ HELP WILL GIVE 50 POINTS - QUADRATIC APPLICATIONS

Mathematics
1 answer:
Contact [7]3 years ago
6 0

Answer:

The bird will be at a ground distance of 10.04 units away.

Step-by-step explanation:

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

f(x) = ax^{2} + bx + c

It's vertex is the point (x_{v}, y_{v})

In which

x_{v} = -\frac{b}{2a}

y_{v} = -\frac{\Delta}{4a}

Where

\Delta = b^2-4ac

If a<0, the vertex is a maximum point, that is, the maximum value happens at x_{v}, and it's value is y_{v}.

Equation for the height:

The height of the bird after x seconds is given by:

h(x) = -0.114x^2 + 2.29x + 3.5

Which is a quadratic equation with a = -0.114, b = 2.29, c = 3.5.

When the bird is at its highest?

Quadratic equation with a < 0, and thus, at the vertex. The ground distance is the x-value of the vertex. Thus

x_{v} = -\frac{b}{2a} = -\frac{2.29}{2(-0.114)} = 10.04

The bird will be at a ground distance of 10.04 units away.

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Pls answer. i will mark u as branliest
Artemon [7]

Answer:

540°

Step-by-step explanation:

The sum of the interior angles of a polygon is

sum = 180° (n - 2) ← n is the number of sides

A pentagon has n = 5, thus

sum = 180° × 3 = 540°

3 0
3 years ago
Write the following decimals as fractions.
GaryK [48]

Hi there! Hopefully this helps!

-------------------------------------------------------------------------------------------------------

<em>0.77</em><em> </em><em>as a </em><u><em>fraction</em></u><em> is </em><u><em>77/100</em></u><em>.</em>

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

<em>0.2904 as a </em><u><em>fraction</em></u><em> is </em><u><em>2904⁄10000</em></u><em> </em><u><em>unsimplified</em></u><em>. (Simplified would be </em><u><em>363⁄1250</em></u><em>)</em>

6 0
4 years ago
Read 2 more answers
2. Let A, B and c be three towers. The bearing of B from A is 120° and angle BC is 68º. The distance from Tower A to Tower B is
g100num [7]

(i) The bearing of B from A and angle x are supplementary, then:

\begin{gathered} 120\degree+x=180\degree \\ x=180\degree-120\degree \\ x=60\degree \end{gathered}

(ii)

From the above diagram, the bearing angle of A from B is:

120\degree+180\degree=300\degree

(iii)

From the above diagram, the bearing angle of C from B is:

180\degree+52\degree=232\degree

(iv)

Applying the law of cosines with the sides AB = 145m and CB = 240 m, and the angle ABC = 68°, the distance AC is:

\begin{gathered} AC^2=AB^2+CB^2-2\cdot AB\cdot CB\cdot cos\left(\angle ABC\right) \\ AC^2=145^2+240^2-2\cdot145\cdot240\cdot cos(68\degree) \\ AC^2=21025+57600-69600\cdot cos(68\operatorname{\degree}) \\ AC^2=52552.3811 \\ AC=\sqrt{52552.3811} \\ AC\approx229\text{ m} \end{gathered}

6 0
1 year ago
9 + n/2 &gt; 16<br>show work please
iVinArrow [24]

1. write the division as a fraction
9+n/2>16 → 9+1/2n>16
2. multiply both sides of the inequality by 2
2x9+2x1/2n>2x16
3. multiply the numbers and reduce the numbers with greatest common divisor 2 (remove number 2, the common factor from equation)
18+n>32
4. move constant to the right by adding its opposite to both sides
18+n-18>32-18
5. eliminate the opposites
n>32-18
6. subtract the numbers
n>14
hope this helped!
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3 years ago
Match each polynomial expression to is additive inverse
andriy [413]

Answer:

<em>hope</em><em> </em><em>y</em><em>o</em><em>u</em><em> </em><em>get</em><em> </em><em>it</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

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