It would be 27 divided by 5 which would be 5.4, so the answer would be y=5.4
Answer:
The system of equations 8x-3y=10 and 16x-6y=22 has no solution
Step-by-step explanation:
When both of the above equations are put into standard form, you get ...
8x - 3y = 10
8x - 3y = 11
This is an "inconsistent" pair of equations. There are no values of x and y that can satisfy both equations, hence there is no solution.
Answer:
105 dollars saved
Step-by-step explanation:
She only gave you 45 to start 3 times 20 is 60+45=105
No they won’t be.Consider the linear combination (1)(u – v) + (1) (v – w) + (-1)(u – w).This will add to 0. But the coefficients aren’t all 0.Therefore, those vectors aren’t linearly independent.
You can try an example of this with (1, 0, 0), (0, 1, 0), and (0, 0, 1), the usual basis vectors of R3.
That method relied on spotting the solution immediately.If you couldn’t see that, then there’s another approach to the problem.
We know that u, v, w are linearly independent vectors.So if au + bv + cw = 0, then a, b, and c are all 0 by definition.
Suppose we wanted to ask whether u – v, v – w, and u – w are linearly independent.Then we’d like to see if there are non-zero coefficients in the linear combinationd(u – v) + e(v – w) + f(u – w) = 0, where d, e, and f are scalars.
Distributing, we get du – dv + ev – ew + fu – fw = 0.Then regrouping by vector: (d + f)u + (-d +e)v + (-e – f)w = 0.
But now we have a linear combo of u, v, and w vectors.Therefore, all the coefficients must be 0.So d + f = 0, -d + e = 0, and –e – f = 0. It turns out that there’s a free variable in this solution.Say you let d be the free variable.Then we see f = -d and e = d.
Then any solution of the form (d, e, f) = (d, d, -d) will make (d + f)u + (-d +e)v + (-e – f)w = 0 a true statement.
Let d = 1 and you get our original solution. You can let d = 2, 3, or anything if you want.
Answer:
-2
Step-by-step explanation:
The equation is -12/c=6
by solving for c you get,
-12/c=6
Then multiply both sides by the LCM c to get, -12=6c
Divide both sides by 6 to get,
-12/6=6c/6
-2=c
Verification:
-12/-2=6 since when a negative number divides a negative number the answer is a positive value
