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FinnZ [79.3K]
3 years ago
12

Given that the value of b can never be equal to -1, determine if the equations are intersecting, parallel, or coincident. x + y

= ab bx - y = a
Mathematics
2 answers:
lora16 [44]3 years ago
7 0
I'm pretty sure its intersecting. 
vitfil [10]3 years ago
6 0
Intersecting i believe?
You might be interested in
-3/4x < 12
Maksim231197 [3]
Okay, so, to solve these inequalities, your goal is to get the variable equal to one number, so let's take a look at the first problem:

-3 / 4x < 12,

to get rid of the numbers attached to the variable 'x', you would divide the numbers, since, the original is multiplying with x, you would do the opposite, and the opposite of multiplication, is division.

So, now our equation is, - 3 / 4x divided by - 3 / 4, which would leave X by itself, then we have to do that same thing to the 12, which would be, 12 divided by - 3 / 4, which would equal, 16.

-3 / 4 < 12
÷ - 3 / 4 ÷ - 3 / 4
_____________
X > 16

Now, our equation is X > 16, which is the answer, to problem number one.

(Also a quick note, when you divide by a negative, the inequality symbol flips, for example, when we divided by -3 / 4, our inequality symbol changed from the less than symbol, to the more than symbol.)

___________________________________

Let's take a look at problem number two:

13c < -169,

Okay, so, again, you're trying to get C by itself. The number 13 is multiplying with C, so, you need to do the opposite, and divide, so you can get C by itself.

13c divided by 13 equals C

13c/13 = C

and

- 169 divided by 13, equals, -13,

So, the answer is, C < -13

Or,

13c < - 169
÷ 13 ÷ 13
__________
C < - 13
___________________________________

Let's take a look at problem number 3:

5B - 28 > 27,

Okay, so now, we have another number on the same side as B, so, we get rid of that first, it's subtracting, so now we do the opposite, and add it to the other side.

5B - 28 > 27
+28 +28
__________
5B > 55

Now, we divide both sides by 5:

5B > 55
÷5 ÷5
_______

B > 5
___________________________________

Now, Let's take a look at problem number 4:

3x - 7 > 4x + 2,

okay, so, we have multiple steps to take with this equation.

First, we want to get X by itself, so, we have to get rid of the -7, so, we do the opposite, and the opposite of subtracting, is adding.

3x - 7 > 4x + 2
+ 7 + 7
___________
3x > 4x + 9

Now, you only want to have one number with X, per equation, so, you need to move 4x to the other side, the way we do that, is by subtracting 4x.

3x > 4x + 9
-4x -4x
__________
-1x > 9

We can't have a negative number attached to the x, because that's like having a negative X, so, we have to divide one more time.

-1x > 9
÷-1 ÷-1
_______

Since, we are dividing by a negative, the inequality sign is going to flip, which would make the answer:

X < -9
___________________________________

I hope this helps!
3 0
4 years ago
I need help asp
Fynjy0 [20]

Answer:

3627

Step-by-step explanation:

assuming it is 13*(-32.48-14.02)*6

4 0
3 years ago
You buy a new computer for $1,500. The value of the computer decreases by 6%
Naya [18.7K]

Answer:

$1171.05

Step-by-step explanation:

1500 × (1-(6 / 100))⁴

5 0
3 years ago
Read 2 more answers
A consumer group selected 100 different airplanes at random from each of two large airlines. The mean seat width for the 100 air
Novay_Z [31]

Answer:

Decreasing the sample size decreases the width of the confidence interval.

Step-by-step explanation:

-Let s be the sample standard deviation and \bar X be the sample mean.

#We calculate the 95% confidence interval for the sample size 100 as below:

\bar X\pm z_{0.05/2}\frac{s}{\sqrt{n}}\\\\\\=\bar X\pm 1.960\times\frac{s}{\sqrt{50}}\\\\\\=\bar X\pm 0.1960s

#we then calculate the confidence interval of sample size =50 and of similar mean and standard deviation:

\bar X\pm z\frac{s}{\sqrt{n}}\\\\\\=\bar X\pm z_{0.05/2}\times\frac{s}{\sqrt{n}}\\\\\\=\bar X\pm1.960\times \frac{s}{\sqrt{50}}\\\\\\\\=\bar X\pm0.2772s

#Notice that the smaller sample(n=50) has a narrower confidence interval.

Hence, decreasing the sample size decreases the width of the confidence interval.

6 0
3 years ago
Read 2 more answers
Relative density was determined for one sample of second-growth Douglas fir 2 x 3 4s with a low percentage of juvenile wood and
Citrus2011 [14]

Answer:

0.03865

Step-by-step explanation:

Since the true density for the two types of trees are given, we would evaluate the average for both of them

Low percentage of juvenile wood density = 0.523 and 0.0543

Average density = 0.523 + 0.0543/2

Average density = 0.55015

Moderate percentage of juvenile wood density = 0.489 and 0.0450

Average density = 0.489 + 0.0450/2

Average density = 0.5115

Therefore, difference in true average density for the two woods are = 0.55015 - 0.51150

= 0.03865

5 0
3 years ago
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