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stiks02 [169]
3 years ago
11

Solve the equation. 5/6x - 4 = -2

Mathematics
1 answer:
Agata [3.3K]3 years ago
8 0

Answer:

A

Step-by-step explanation:

Given

\frac{5}{6} x - 4 = - 2 ( add 4 to both sides )

\frac{5}{6} x = 2 ( multiply both sides by 6 to clear the fraction )

5x = 12 ( divide both sides by 5 )

x = \frac{12}{5} = 2 \frac{2}{5} → A

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Answer:

The answer to this question is c

Step-by-step explanation:

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3 years ago
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A ship is stationary at sea. A tugboat is 28 km away at a bearing of 315°, and a yacht is 21 km from the tugboat at a bearing of
aleksley [76]

The distance of the yacht from the ship is found by accurately drawing

the relative location of the three vessels.

Response:

  • The measured distance of the yacht from the ship is approximately <u>30 km</u>.

<h3>Which drawing method can be used in which the distance of the yacht from the ship can be measured?</h3>

The given parameters are;

Distance of the tugboat from the ship, a = 28 km

Bearing of tugboat from the ship = 315°

Distance of the yacht from the tugboat, b = 21 km

Bearing of the yacht from the = 210°

Using a scale of 1 : 350,000, we have;

The \ drawing \ of \ a = \mathbf{\dfrac{28,000}{350,000} }= 0.08

The length of <em>a</em> in the drawing = 0.08 m = 8 cm

The \ drawing \ of \ b =  \mathbf{\dfrac{21,000}{350,000}} = 0.06

Which gives;

<em>b</em> in the drawing = 0.06 m = 6 cm

Using the above dimensions and directions, the drawing of the relative

location of the three vessels can be accurately created using MS Word.

From the application, the vector form of the distance, <em>d</em>, of the ship from the yacht is presented as follows;

  • d = 8.655·i + 0.445·j

Which gives;

d = √(8.655² + 0.445²) = 8.67

Which gives;

  • Distance of the yacht from the ship on the drawing is d ≈ 8.67 cm = 0.0867 m

Actual distance = 0.0867 m × 350,000 = 30,345 m = 30.345 km ≈ 30 km

  • The distance of the yacht from the ship ≈ <u>30 km</u>

Using cosine rule, where the angle formed at the tugboat = 75°, we have;

d² = 28² + 21² - 2 × 28 × 21 × cos(75°) ≈ 920.63

Which gives;

d ≈ √(920.63) ≈ 30

The distance of the yacht from the ship, d ≈ 30 km

Learn more about bearings in mathematics here:

brainly.com/question/10710413

3 0
2 years ago
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Can anyone help me please :( !
V125BC [204]

Answer:

D=3x+5, I=4x+8, -1x-3

Step-by-step explanation:

You don't know how many chocolates are in the boxes, so that's x. Always look at "and" and think + something. You know how many extra chocolates there are so you don't need to put the x. Remember, and=plus. Remember the equation is Mx+b.

The two expressions together is 3x+5=4x+8. Move the 4x to the other side with 3x+5 and make it negative. Same for eight. Hopefully that helps.

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2 years ago
Which of the following represent the general term for the sequence 2,4,6,8,10...
vitfil [10]

Answer:

they're counting by 2's

Step-by-step explanation:

2,4,6,8,10,12,14,16,18,20

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3 years ago
C^2 = 27<br><br> Pls help me I’m doing my missing math work :,)
LekaFEV [45]
Answer c=5.196
c=sqrt(27)
c=5.196
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3 years ago
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