1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
stiks02 [169]
3 years ago
11

Solve the equation. 5/6x - 4 = -2

Mathematics
1 answer:
Agata [3.3K]3 years ago
8 0

Answer:

A

Step-by-step explanation:

Given

\frac{5}{6} x - 4 = - 2 ( add 4 to both sides )

\frac{5}{6} x = 2 ( multiply both sides by 6 to clear the fraction )

5x = 12 ( divide both sides by 5 )

x = \frac{12}{5} = 2 \frac{2}{5} → A

You might be interested in
How do u solve it, I'm stuck please help.
allochka39001 [22]
I think it’s 3 I’m not sure
3 0
3 years ago
Read 2 more answers
Which expression is equivalent to 4^7 x 4^-5​
melisa1 [442]
<h2>4⁷×4⁵</h2><h3>{a^m×a^n=a^(m×n)}</h3><h3>=4^(⁷×-⁵)</h3><h3>=4^-35</h3>

please mark this answer as brainlist

3 0
3 years ago
Can someone pls help thanks
kolezko [41]
I think I think that it is 8 hours. Hopefully that helps!
5 0
3 years ago
You have a large jar that initially contains 30 red marbles and 20 blue marbles. We also have a large supply of extra marbles of
Dima020 [189]

Answer:

There is a 57.68% probability that this last marble is red.

There is a 20.78% probability that we actually drew the same marble all four times.

Step-by-step explanation:

Initially, there are 50 marbles, of which:

30 are red

20 are blue

Any time a red marble is drawn:

The marble is placed back, and another three red marbles are added

Any time a blue marble is drawn

The marble is placed back, and another five blue marbles are added.

The first three marbles can have the following combinations:

R - R - R

R - R - B

R - B - R

R - B - B

B - R - R

B - R - B

B - B - R

B - B - B

Now, for each case, we have to find the probability that the last marble is red. So

P = P_{1} + P_{2} + P_{3} + P_{4} + P_{5} + P_{6} + P_{7} + P_{8}

P_{1} is the probability that we go R - R - R - R

There are 50 marbles, of which 30 are red. So, the probability of the first marble sorted being red is \frac{30}{50} = \frac{3}{5}.

Now the red marble is returned to the bag, and another 3 red marbles are added.

Now there are 53 marbles, of which 33 are red. So, when the first marble sorted is red, the probability that the second is also red is \frac{33}{53}

Again, the red marble is returned to the bag, and another 3 red marbles are added

Now there are 56 marbles, of which 36 are red. So, in this sequence, the probability of the third marble sorted being red is \frac{36}{56}

Again, the red marble sorted is returned, and another 3 are added.

Now there are 59 marbles, of which 39 are red. So, in this sequence, the probability of the fourth marble sorted being red is \frac{39}{59}. So

P_{1} = \frac{3}{5}*\frac{33}{53}*\frac{36}{56}*\frac{39}{59} = \frac{138996}{875560} = 0.1588

P_{2} is the probability that we go R - R - B - R

P_{2} = \frac{3}{5}*\frac{33}{53}*\frac{20}{56}*\frac{36}{61} = \frac{71280}{905240} = 0.0788

P_{3} is the probability that we go R - B - R - R

P_{3} = \frac{3}{5}*\frac{20}{53}*\frac{33}{58}*\frac{36}{61} = \frac{71280}{937570} = 0.076

P_{4} is the probability that we go R - B - B - R

P_{4} = \frac{3}{5}*\frac{20}{53}*\frac{25}{58}*\frac{33}{63} = \frac{49500}{968310} = 0.0511

P_{5} is the probability that we go B - R - R - R

P_{5} = \frac{2}{5}*\frac{30}{55}*\frac{33}{58}*\frac{36}{61} = \frac{71280}{972950} = 0.0733

P_{6} is the probability that we go B - R - B - R

P_{6} = \frac{2}{5}*\frac{30}{55}*\frac{25}{58}*\frac{33}{63} = \frac{49500}{1004850} = 0.0493

P_{7} is the probability that we go B - B - R - R

P_{7} = \frac{2}{5}*\frac{25}{55}*\frac{1}{2}*\frac{33}{63} = \frac{825}{17325} = 0.0476

P_{8} is the probability that we go B - B - B - R

P_{8} = \frac{2}{5}*\frac{25}{55}*\frac{1}{2}*\frac{30}{65} = \frac{750}{17875} = 0.0419

So, the probability that this last marble is red is:

P = P_{1} + P_{2} + P_{3} + P_{4} + P_{5} + P_{6} + P_{7} + P_{8} = 0.1588 + 0.0788 + 0.076 + 0.0511 + 0.0733 + 0.0493 + 0.0476 + 0.0419 = 0.5768

There is a 57.68% probability that this last marble is red.

What's the probability that we actually drew the same marble all four times?

P = P_{1} + P_{2}

P_{1} is the probability that we go R-R-R-R. It is the same P_{1} from the previous item(the last marble being red). So P_{1} = 0.1588

P_{2} is the probability that we go B-B-B-B. It is almost the same as P_{8} in the previous exercise. The lone difference is that for the last marble we want it to be blue. There are 65 marbles, 35 of which are blue.

P_{2} = \frac{2}{5}*\frac{25}{55}*\frac{1}{2}*\frac{35}{65} = \frac{875}{17875} = 0.0490

P = P_{1} + P_{2} = 0.1588 + 0.0490 = 0.2078

There is a 20.78% probability that we actually drew the same marble all four times

3 0
3 years ago
Can somebody help me out pleaseeee ??
nexus9112 [7]

Answer:

67.5cm^2

Step-by-step explanation:

area of a triangle is 0.5xaxb

5 0
2 years ago
Read 2 more answers
Other questions:
  • Can someone please help me out?
    5·2 answers
  • Find the area of the triangle SHOW WORK
    15·1 answer
  • Hannah has a grid a squares that has 12 rows with 15 squares in each row.She colors 5 rows of 8 squares in the middle of the gri
    8·2 answers
  • Stephanie ran four laps around the school track in 7min and 30 sec how many sec per lap is that
    11·1 answer
  • Y= 9x + 7 over 3 rewrite in standard form
    9·2 answers
  • Evaluate the expression <br> 4^2-13
    12·2 answers
  • Martha earned a gross pay of $1,215.60 last week. Using the fact that
    11·1 answer
  • The school cafeteria is offering a choice of two side dishes at lunch today, either watermelon or french fries. The ratio of the
    8·1 answer
  • Need answer ASAP
    12·1 answer
  • Help me please need help​
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!