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alexandr402 [8]
2 years ago
10

Plsssssss helpgot 20 mins​the question is: The sin of angle DCB is

Mathematics
1 answer:
Elena L [17]2 years ago
5 0

Answer:

i. <DCB = 53.13^{o}

ii. Sin of <DCB = 0.8

Step-by-step explanation:

Let <DCB be represented by θ, so that;

Sin θ = \frac{opposite}{hypotenuse}

Thus from the given diagram, we have;

Sin θ = \frac{4}{5}

        = 0.8

This implies that,

θ = Sin^{-1} 0.8

   = 53.1301

θ = 53.13^{o}

Therefore, <DCB = 53.13^{o}.

So that,

Sin of <DCB = Sin 53.13^{o}

                    = 0.8

Sin of <DCB = 0.8

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