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3 years ago

PLS HELPP!!!! Find f(-5) if f(x)=|x+1| a.6 b.5 c.4

Mathematics

1 answer:

natka813 [3]3 years ago

4 0

The answer is 4 because, -5+1 is -4 then the absolute value of -4 is 4. Hope this helps

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Graph the function. y=5 (x+1) ^2 -3

ra1l [238]

Answer:

Step-by-step explanation:

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3 years ago

Anderson has $50 in his savings account. He deposits $5 every week. His father also deposits $20 into the account every time And

Sav [38]

Part A: 5 is the coefficient, w is the variable, 50 is the constant

Part B: 10 x 5 = 50 + 2 x 20 = 40+ 50 = $140

Part C: the constant,50,would change and become 85. Hope this helps :)

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3 years ago

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Sonbull [250]

Answer:

$y\ =\ \left|\frac{1}{2}x-2.5\right|+3$

Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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3 years ago

A randomly selected sample of n =51 men in Brazil had an average lifespan of 59 years. The standard deviation was 10 years. Calc

Aloiza [94]

Answer:

$59-2.40\frac{10}{\sqrt{51}}=55.639$

$59+ 2.40\frac{10}{\sqrt{51}}=62.361$

The 98% confidence interval would be given by (55.639;62.361)

Step-by-step explanation:

Information given

$\bar X= 59$ represent the sample mean

$s= 10$ represent the sample deviation

$n= 51$ represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=51-1=50$

The Confidence is 0.98 or 98%, the significance would be $\alpha=0.02$ and $\alpha/2 =0.01$ ,and the critical value would be $t_{\alpha/2}=2.40$

And replacing we got:

$59-2.40\frac{10}{\sqrt{51}}=55.639$

$59+ 2.40\frac{10}{\sqrt{51}}=62.361$

The 98% confidence interval would be given by (55.639;62.361)

3 0

3 years ago