-6b = -66
You divide -6 on both sides. A negative multiplied/divided by a negative equals a positive
-1 · -1 = 1
-1 ÷ -1 = 1
b = 11
Answer:
intercept 
line 
Step-by-step explanation:
Let
is the required line.
<u>Slope of perpendicular lines :</u> If
and
be slope of two perpendicular lines. Them 
is perpendicular to 
the slope of
is 

Hence eqn is 
This equation passes through 

so the line is 
<u>y-intercept :</u>
Substitute 

H(17) = 17
Do you need help with the other 2?
Given a polynomial
and a point
, we have that

We know that our cubic function is zero at -4, 0 and 5, which means that our polynomial is a multiple of

Since this is already a cubic polynomial (it's the product of 3 polynomials with degree one), we can only adjust a multiplicative factor: our function must be

To fix the correct value for a, we impose
:

And so we must impose

So, the function we're looking for is

Hi there!

To find the indefinite integral, we must integrate by parts.
Let "u" be the expression most easily differentiated, and "dv" the remaining expression. Take the derivative of "u" and the integral of "dv":
u = 4x
du = 4
dv = cos(2 - 3x)
v = 1/3sin(2 - 3x)
Write into the format:
∫udv = uv - ∫vdu
Thus, utilize the solved for expressions above:
4x · (-1/3sin(2 - 3x)) -∫ 4(1/3sin(2 - 3x))dx
Simplify:
-4x/3 sin(2 - 3x) - ∫ 4/3sin(2 - 3x)dx
Integrate the integral:
∫4/3(sin(2 - 3x)dx
u = 2 - 3x
du = -3dx ⇒ -1/3du = dx
-1/3∫ 4/3(sin(2 - 3x)dx ⇒ -4/9cos(2 - 3x) + C
Combine:
