Using it's concept, it is found that there is a 0.0366 = 3.66% probability that your coach and your friend get orange and you get a fruit-punch.
<h3>What is a probability?</h3>
A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.
In this problem, there are 15 bottles.
- 5 are orange, hence the is a 5/15 = 1/3 probability that the coach gets orange, hence P(A) = 1/3.
- After the coach, there will be 14 bottles remaining, of which 4 are orange, hence the probability that the friend gets orange is of P(B) = 4/14 = 2/7.
- For you, there will be 13 bottles remaining, of which 5 will be of fruit-punch, hence the probability you get fruit-punch is of P(C) = 5/13.
The probability of the three outcomes occurring is given by:
0.0366 = 3.66% probability that your coach and your friend get orange and you get a fruit-punch.
More can be learned about probabilities at brainly.com/question/14398287
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Answer:
X= 15
Step-by-step explanation:
multiply 5 on x/5 and 9
divide 3 and 45
x=15
Answer:
124 ft2
Step-by-step explanation:
The yard is a 12ft square so the length and width would both be 12ft. You multiply the length and width of the yard to get the area of the yard so 12x12=144. You have the length and width of the flower bed so 5x4=20. Once you have the area of both you can subtract the area the flower bed takes up of the lawn. 144-20=124 ft2.
Answer:
its simple its C
Step-by-step explanation:
forget humanity and return to monke
Answer:
y=x, x-axis, y=x, y-axis
Explanation:
Reflecting the figure across three axes just moves it from one quadrant to another. It does not map the figure to itself.
Reflecting across the line y=x moves it from quadrant II to IV or vice-versa. If it is in quadrant I or III, it stays there. So the sequence of reflections x-axis (moves from I to IV), y=x (moves from IV to II), x-axis (moves from II to III), y=x (stays in III) will not map the figure to itself.
However, the last selection will map the figure to itself. The initial (and final) figure location, and the intermediate reflections are shown in the attached. The figure starts and ends as blue, is reflected across y=x to green, across x-axis to orange, across y=x to red, and finally across y-axis to blue again.
