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Finger [1]
3 years ago
12

If an event of probability p is observed repeatedly during independent repetitions, the ratio of the observed frequency of that

event to the total number of repetitions approaches p as the number of repetitions becomes arbitrarily large. Which choice matches the definition? A) Binomial Experiment B) theoretical probability C) The law of large numbers D) experimental probability
Mathematics
2 answers:
avanturin [10]3 years ago
5 0

Answer:

The correct answer is The law of large numbers.

Step-by-step explanation:

so c will be your answer

Arlecino [84]3 years ago
3 0

Answer:

b

Step-by-step explanation:

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Verify cot x sec^4x=cotx +2tanx +tan^3x
Tanzania [10]

Answer:

See explanation

Step-by-step explanation:

We want to verify that:

\cot(x)  \:  { \sec}^{4} x =  \cot(x) + 2 \tan(x)   +  { \tan}^{3} x

Verifying from left, we have

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \: ( 1 +  { \tan}^{2} x )^{2}

Expand the perfect square in the right:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \: ( 1 +  { 2\tan}^{2} x  + { \tan}^{4} x)

We expand to get:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  \cot(x){ 2\tan}^{2} x  +\cot(x) { \tan}^{4} x

We simplify to get:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  2 \frac{ \cos(x) }{\sin(x) ) }  \times  \frac{{ \sin}^{2} x}{{ \cos}^{2} x}   +\frac{ \cos(x) }{\sin(x) ) }  \times  \frac{{ \sin}^{4} x}{{ \cos}^{4} x}

Cancel common factors:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  2 \frac{{ \sin}x}{{ \cos}x}   +\frac{{ \sin}^{3} x}{{ \cos}^{3} x}

This finally gives:

\cot(x)  \:  { \sec}^{4} x =  \cot(x) + 2 \tan(x)   +  { \tan}^{3} x

3 0
3 years ago
Slope is 2 and (−1, 6) is on the line; point-slope form
MissTica

Answer:

y-6=2(x-(-1))

Or simplified:

y-6=2(x+1)

Step-by-step explanation:

use the formula: y-y1=m(x-x1)

8 0
3 years ago
Given the geometric sequence where a1=1 and the common ratio is 6, what is the domain for n?​
kari74 [83]

We have been given that a geometric sequence's 1st term is equal to 1 and the common ratio is 6. We are asked to find the domain for n.

We know that a geometric sequence is in form a_n=a_1(r)^{n-1}, where,

a_n = nth term of sequence,

a_1 = 1st term of sequence,

r = Common ratio,

n = Number of terms in a sequence.

Upon substituting our given values in geometric sequence formula, we will get:

a_n=1\cdot (7)^{n-1}

Our sequence is defined for all integers such that n is greater than or equal to 1.

Therefore, domain for n is all integers, where n\geq 1.

4 0
3 years ago
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Answer:

what is Never Have I Ever

Step-by-step explanation:

7 0
3 years ago
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