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Mumz [18]
3 years ago
7

Please help me with this

Mathematics
1 answer:
IgorC [24]3 years ago
3 0
It would be 3 and a half because 4 is too much
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trapecia [35]

Answer:

option A

Step-by-step explanation:

given,

sample of tritium, ³H

t_{1/2} = 12.32 years

contents present of ³H = 5.25 mol

content of ³He = 6.35 mol

reaction

 ^3H\rightarrow \ ^3He

A₀ is the initial concentration

At is the concentration after time t

A₀ = 5.25 + 6.35 = 11.6 mol

At = 5.25

now,

  k = \dfrac{0.693}{t_{1/2}}

  k = \dfrac{0.693}{12.32}

           k = 0.0563 /year

ln(\dfrac{A_o}{A_t}) = k t

t = \dfrac{1}{k} ln(\dfrac{A_o}{A_t})

t = \dfrac{1}{0.0563} ln(\dfrac{11.6}{5.25})

t = 14.1 yr

hence, the correct answer is option A

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