3 years ago

Yea I need please 3/4 divided by 2/3

Mathematics

1 answer:

mr Goodwill [35]3 years ago

4 0

Answer:

1.125

Step-by-step explanation:

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Answer:

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Explanation:

Assuming the correct expression is to find the following limit:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}$

Use the property the limit of the quotient is the quotient of the limits:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}$

Evaluate the numerator:

$\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}=\frac{1^2-1}{\lim_{x \to1}sin(x-2)}=\frac{0}{\lim_{x \to 1}sin(x-2}$

Evaluate the denominator:

Since $\lim_{x \to1}sin(x-2)\neq 0$

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3 years ago

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Answer:

Step-by-step explanation:

Let the number = x

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7x - 5x + 1 = 5x - 5x + 25 Combine

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2x + 1 - 1 = 25-1 Combine

2x = 24 Divide by 2

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x = 12

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