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3 years ago

Find the gain percent in the following:Cost Price Rs 280,(a) Selling PriceRs 290

Mathematics

1 answer:

Nikolay [14]3 years ago

4 0

Answer:

3.57

Step-by-step explanation:

P=SP -CP

=290-280=10

P%= $\frac{P*100}{CP}$

= $\frac{10*100}{280}$

= $\frac{1000}{280}$

=3.57

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Answer:

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Step-by-step explanation:

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2 years ago

Suppose quantity s is a length and quantity t is a time. Suppose the quantities v and a are defined by v = ds/dt and a = dv/dt.

finlep [7]

Answer:

a) $v = \frac{[L]}{[T]} = LT^{-1}$

b) $a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

c) $\int v dt = s(t) = [L]=L$

d) $\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

e) $\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

s(t) a position function

$v = \frac{ds}{dt}$

$a= \frac{dv}{dt}$

Part a

If we do the dimensional analysis for v we got:

$v = \frac{[L]}{[T]} = LT^{-1}$

Part b

For the acceleration we can use the result obtained from part a and we got:

$a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

Part c

From definition if we do the integral of the velocity respect to t we got the position:

$\int v dt = s(t)$

And the dimensional analysis for the position is:

$\int v dt = s(t) = [L]=L$

Part d

The integral for the acceleration respect to the time is the velocity:

$\int a dt = v(t)$

And the dimensional analysis for the position is:

$\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

Part e

If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:

$\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

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2 years ago

Financial Algebra 1. Unit 1: Simple and Compound Interest Quiz A..

Nikolay [14]

Answer:

$56,558.1

Step-by-step explanation:

This is a question on compound interest.

The formula to calculate the Total Amount based on compound interest is given as:

A = P( 1 + r/n) ^nt

A = Total or Final amount in the account after t years

P = Principal/ Initial amount invested=$35,000

r = Interest rate = 12%

n = compounding Frequency = daily = using 30 days in a month = 30 × 12 = 360 days

t = time in years = 4

A = $35,000( 1 + 0.12/360)^360 × 4

A = $56558.08

Approximately to the nearest cent ≈ A = $56,558.1

Therefore, Priscilla should be expecting $56,558.1 in the account after 4 years.

8 0

2 years ago

The quadrilaterals ABCD and PQRS are similar. Find the length X of SP.

BaLLatris [955]

Answer:

$x = 3.6$

Step-by-step explanation:

Since Quadrilateral ABCD ~ PQRS, therefore:

$\frac{AB}{PQ} = \frac{BC}{QR} = \frac{CD}{RS} = \frac{DA}{SP}$

Let's find the value of x by using the ratio of two corresponding sides of both quadrilaterals. Let's use:

$\frac{CD}{RS} = \frac{DA}{SP}$

CD = 5

RS = 4.5

DA = 4

SP = x

$\frac{5}{4.5} = \frac{4}{x}$

Cross multiply

$5*x = 4.5*4$

$5x = 18$

Divide both sides by 5

$x = \frac{18}{5}$

$x = 3.6$

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3 years ago

What is the sum of -2 + (-5)?

Misha Larkins [42]

Answer:

-7

Step-by-step explanation:

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3 years ago

Read 2 more answers

Find the gain percent in the following:Cost Price Rs 280,(a) Selling PriceRs 290​

Find the gain percent in the following:Cost Price Rs 280,(a) Selling PriceRs 290