<em>372₁₀ = 2442₅</em>
- Step-by-step explanation:
<em>372 : 5 = 74 r 2</em>
<em>74 : 5 = 14 r 4</em>
<em>14 : 5 = 2 r 4</em>
<em>2 : 5 = 0 r 2 ↑</em>
<em>write down the remainders in the reverse order</em>
<em />
<em>372₁₀ = 2442₅</em>
Answer:
<h2>
Therefore the length of a side of a cube is ![\sqrt[3]{64}\ or\ 4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%5C%20or%5C%204)
</h2>
Step-by-step explanation:
The volume of a cube is expressed as L³ where L is the length of each side of the cube.
Given volume of a cube = 64in³
On substituting;
64 = L³
Taking the cube root of both sides to determine L we have;
![\sqrt[3]{64} = (\sqrt[3]{L})^{3}\\\sqrt[3]{64} = L\\L=4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%20%3D%20%28%5Csqrt%5B3%5D%7BL%7D%29%5E%7B3%7D%5C%5C%5Csqrt%5B3%5D%7B64%7D%20%3D%20L%5C%5CL%3D4)
Therefore the length of a side of a cube is ![\sqrt[3]{64}\ or\ 4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%5C%20or%5C%204)
This is a division problem. You can use the standard algorithm of 128/ 5. Or you can create equal groups (draw five circles) and count out eggs until you distribute them all. I would start with 20 in each circle. That would be 20+ 20+ 20+ 20+ 20= 100 Then think 128-100= 28 Next count by 5's. 5+ 5+ 5+ 5+ 5= 25 Then think what is 28-25= 3 so 128/ 5= 25 with a reminder of 3 eggs left over.
The second one I beileve is the answer to your question