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amid [387]
3 years ago
5

I need help with this, due like right now!

Mathematics
1 answer:
adelina 88 [10]3 years ago
7 0

Answer:

njhbgvfcdxcfvgbh

Step-by-step explanation:

nhgvf

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9. John bought a used truck for $4,500. He made an agreement with the dealer to put $1,500 down and make payments of $350 for th
kirza4 [7]

Answer:

11.111111111111111...%

6 0
3 years ago
A manufacturer knows that their items have a normally distributed length, with a mean of 15.4 inches, and standard deviation of
Masteriza [31]

Answer:

0.9452 = 94.52% probability that their mean length is less than 16.8 inches.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 15.4 inches, and standard deviation of 3.5 inches.

This means that \mu = 15.4, \sigma = 3.5

16 items are chosen at random

This means that n = 16, s = \frac{3.5}{\sqrt{16}} = 0.875

What is the probability that their mean length is less than 16.8 inches?

This is the p-value of Z when X = 16.8. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{16.8 - 15.4}{0.875}

Z = 1.6

Z = 1.6 has a p-value of 0.9452.

0.9452 = 94.52% probability that their mean length is less than 16.8 inches.

5 0
3 years ago
Jerry has a miniature model of a boat. He knows that the boat is 3 3/4 inches wide and 5 1/2 inches long. What is the actual len
FromTheMoon [43]

Width of the miniature model = 3\frac{3}{4} inches

Length of the miniature model = 5\frac{1}{2} inches

The actual width of the boat = 15 feet

Let us find the actual length of the boat.

Write it in a proportion form.

width of model : length of model : : width of actual : length of actual

$\Rightarrow 3\frac{3}{4}:5\frac{1}{2}::15:x

$\Rightarrow\frac{15}{4}:\frac{11}{2}::15:x

$\Rightarrow\frac{\frac{15}{4}}{\frac{11}{2}} =\frac{15}{x}

Do cross multiplication.

$\Rightarrow{\frac{15}{4}x =15\times\frac{11}{2}

$\Rightarrow{\frac{15}{4}x =\frac{165}{2}

$\Rightarrow x =\frac{165}{2}\times{\frac{4}{15}

⇒ x = 22

Hence the actual length of the boat is 22 feet.

6 0
4 years ago
Will someone plz help<br><br> by the way funny photo
Artist 52 [7]

110.859

Hi its me again

8 0
3 years ago
Read 2 more answers
Helppppppp!!!! Please
ValentinkaMS [17]
Last option is your answer ( 0.00000991)
4 0
3 years ago
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