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2 years ago

(3+1/2) ×12. multiple or divide

Mathematics

2 answers:

Lelechka [254]2 years ago

4 0

Answer:

Step-by-step explanation:

First do the thing in parenthesis

3 + 1/2 = 7/2

then multiply

7/2 (12) = 42

taurus [48]2 years ago

3 0

Answer:

(3+1/2) x 12 = 42

Step-by-step explanation:

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7 is the right answer to the question

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3 years ago

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A national grocery store chain wants to test the difference in the average weight of turkeys sold in Detroit and the average wei

Arte-miy333 [17]

Answer:

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

The null hypothesis is accepted .

Assume the population variances are approximately the same

Step-by-step explanation:

Explanation:-

Given data a random sample of 20 turkeys sold at the chain's stores in Detroit yielded a sample mean of 17.53 pounds, with a sample standard deviation of 3.2 pounds

The first sample size 'n₁'= 20

mean of the first sample 'x₁⁻'= 17.53 pounds

standard deviation of first sample S₁ = 3.2 pounds

Given data a random sample of 24 turkeys sold at the chain's stores in Charlotte yielded a sample mean of 14.89 pounds, with a sample standard deviation of 2.7 pounds

The second sample size n₂ = 24

mean of the second sample "x₂⁻"= 14.89 pounds

standard deviation of second sample S₂ = 2.7 pounds

Null hypothesis:-H₀: The Population Variance are approximately same

Alternatively hypothesis: H₁:The Population Variance are approximately same

Level of significance ∝ =0.05

Degrees of freedom ν = n₁ +n₂ -2 =20+24-2 = 42

Test statistic :-

$t = \frac{x^{-} _{1} - x_{2} }{\sqrt{S^2(\frac{1}{n_{1} } }+\frac{1}{n_{2} } }$

where $S^{2} = \frac{n_{1} S_{1} ^{2}+n_{2}S_{2} ^{2} }{n_{1} +n_{2} -2}$

$S^{2} = \frac{20X(3.2)^2+24X(2.7)^2}{20+24-2}$

substitute values and we get S² = 40.988

$t= \frac{17.53-14.89 }{\sqrt{40.988(\frac{1}{20} }+\frac{1}{24} )}$

t = 1.3622

Calculated value t = 1.3622

Tabulated value 't' = 2.081

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

Conclusion:-

The null hypothesis is accepted

Assume the population variances are approximately the same.

6 0

2 years ago

The SAT is standardized to be normally distributed with a mean µ = 500 and a standard deviation σ = 100. What percentage of SAT

Aliun [14]

Answer:

34.134%

68.268%

Step-by-step explanation:

Given that:

Mean (m) = 500

Standard deviation (s) = 100

Percentage between 500 and 600

P(500 < x < 600)

P(x < 600) - P(x < 500)

Z = (x - m) / s

P(x < 600)

Z = (600 - 500) /100 = 1

P(x < 500)

Z = (500 - 500) / 500 = 0

P(Z< 1) - P(Z < 0)

0.84134 - 0.5

= 0.34134

= 0.34134 * 100%

= 34.134%

B.) Between 400 and 600

P(x < 400)

Z = (400 - 500) /100 = - 1

P(x < 600)

Z = (600 - 500) / 500 = 1

P(Z< 1 ) - P(Z < - 1)

0.84134 - 0.15866

= 0.68268

= 0.68268 * 100%

= 68.268%

8 0

2 years ago

Factoring using GCF 15cd + 30c^2d^2

olchik [2.2K]

Answer:

15cd(1 + 2cd)

Step-by-step explanation:

greatest common factor is 15cd

$15cd*1 + 15cd*2cd\\= 15cd(1 + 2cd)$

8 0

2 years ago

Factorise 2-y(7-5y) please

hjlf

Answer:
(y - 1)(5y - 2)

Solution:

Factor:
2 - y(7 - 5y)

Apply the Distributive Property:
2 - 7y + 5y²

Reorder the expression:
5y² - 7y + 2

Rewrite the term:
5y² - 5y - 2y + 2

Regroup terms into two proportional parts:
(5y² - 5y) + ( -2y + 2)

Factor Greatest Common Factors out:
5y(y - 1) - 2(y - 1)
(y - 1)(5y - 2)

5 0

2 years ago

(3+1/2) ×12. multiple or divide​

(3+1/2) ×12. multiple or divide