Please help Geometry problem

Mathematics

1 answer:

julsineya [31]3 years ago

6 0

$\bf A(\stackrel{x_1}{-5}~,~\stackrel{y_1}{1})\qquad B(\stackrel{x_2}{-2}~,~\stackrel{y_2}{5}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{5-1}{-2-(-5)}\implies \cfrac{4}{-2+5}\implies \cfrac{4}{3} \\\\[-0.35em] ~\dotfill\\\\ B(\stackrel{x_2}{-2}~,~\stackrel{y_2}{5})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{3})$

$\bf slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{3-5}{5-(-2)}\implies \cfrac{-2}{5+2}\implies -\cfrac{2}{7} \\\\[-0.35em] ~\dotfill \\\\ C(\stackrel{x_2}{5}~,~\stackrel{y_2}{3})\qquad D(\stackrel{x_2}{2}~,~\stackrel{y_2}{-1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies\cfrac{-1-3}{2-5}\implies \cfrac{-4}{-3}\implies \cfrac{4}{3} \\\\[-0.35em] ~\dotfill$

$\bf A(\stackrel{x_1}{-5}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{2}~,~\stackrel{y_2}{-1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies\cfrac{-1-1}{2-(-5)}\implies \cfrac{-2}{2+5}\implies -\cfrac{2}{7}$

You might be interested in

20 points!~ And thanks if you help me.

lions [1.4K]

Answer:

Step-by-step explanation:

C its CCCCCCCCCCCCCC

7 0

3 years ago

On Friday, Oscar sold 2 pitchers of lemon are from his lemonade stand. On Saturday, he sold 1/2 as much lemonade as on Friday. H

Ann [662]

Answer:

The correct answer is 1 pitcher.

Step-by-step explanation:

Oscar sold 2 pitchers of lemon are from his lemonade stand on Friday.

On Saturday, he sold $\frac{1}{2}$ as much lemonade as on Friday.

The number of pitchers of lemon from the lemonade stand which Oscar sold on Saturday is given by $\frac{1}{2}$ × 2 = 1 pitcher.

Thus Oscar sold 1 pitcher on Saturday which is half of the number of pitchers of lemon he could sell on Friday.

4 0

3 years ago

How to do this question plz answer my question

Degger [83]

Answer:

$121.82

Step-by-step explanation:

Okay, this is kind of complex, so let's go step by step.

First, we want to find the area of the rectangular lawn - we can do this by multiplying the length and width. The length is 100 and the width is 45 so $45\cdot100=4500$ m² is the area of the rectangle.

However, there are 3 ponds in which the grass seeds will not be going - so we need to find the area of all 3 of these circles and subtract it from 4500 (our rectangle area).

The area of a circle is represented by the formula $\pi r^2$