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Monica [59]
2 years ago
15

Please help Geometry problem

Mathematics
1 answer:
julsineya [31]2 years ago
6 0

\bf A(\stackrel{x_1}{-5}~,~\stackrel{y_1}{1})\qquad B(\stackrel{x_2}{-2}~,~\stackrel{y_2}{5}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{5-1}{-2-(-5)}\implies \cfrac{4}{-2+5}\implies \cfrac{4}{3} \\\\[-0.35em] ~\dotfill\\\\ B(\stackrel{x_2}{-2}~,~\stackrel{y_2}{5})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{3})


\bf slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{3-5}{5-(-2)}\implies \cfrac{-2}{5+2}\implies -\cfrac{2}{7} \\\\[-0.35em] ~\dotfill \\\\ C(\stackrel{x_2}{5}~,~\stackrel{y_2}{3})\qquad D(\stackrel{x_2}{2}~,~\stackrel{y_2}{-1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies\cfrac{-1-3}{2-5}\implies \cfrac{-4}{-3}\implies \cfrac{4}{3} \\\\[-0.35em] ~\dotfill


\bf A(\stackrel{x_1}{-5}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{2}~,~\stackrel{y_2}{-1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies\cfrac{-1-1}{2-(-5)}\implies \cfrac{-2}{2+5}\implies -\cfrac{2}{7}

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The first floor of a house consists of a kitchen, playroom, and dining room. The areas of the kitchen, playroom, and dining room
Natasha2012 [34]

The area of the kitchen, playroom, and the dining room floor are 84ft², 63ft² and 42ft² respectively

The area of each floor will be:

Kitchen = 4/9 × 189ft² = 84ft²

Playroom = 3/9 × 189ft² = 63ft²

Dinning room = 2/9 × 189ft² = 42ft²

Therefore, the area of the kitchen, playroom and the dining room floor are 84ft², 63ft², and 42ft² respectively.

Read related link on:

brainly.com/question/10662777

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B) Michael has $0 in his account but makes a purchase and overdrafts his account by<br> $75
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Step-by-step explanation:

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Find acceleration of a cheetah running at 0.5 and sect 21 and second three seconds describe the acceleration of the animal.
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Answer:

Initial velocity (u)=o m/s

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Step-by-step explanation:

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Farrah is making a dragon costume for her little brother. It would have triangular spikes down the head and back each head spike
lilavasa [31]

The question is not written properly! Complete question along with answer and explanation is provided below.

Question:

Farrah is making a dragon costume for her little brother. It would have triangular spikes down the head and back.

Each head spike has a base of 2 cm and a height of 6 cm.

Each back spike will be 10 cm high with a base of 6 cm.

if the costume has 6 spikes on the back and on the head 10 more spikes than the back then how many square centimeters of fabric will farrah need for all the dragon spikes?

Given Information:

Base of head spike = b₁ = 2 cm

Height of head spike = h₁ = 6 cm

Base of back spike = b₂ = 6 cm

Height of back spike = h₂ = 10 cm

Number of head spikes = n₁ = 10 + 6 = 16

Number of back spikes = n₂ = 6

Required Information:

How much fabric is needed = ?

Answer:

Farrah would need 276 cm² of fabric for all the dragon spikes.

Step-by-step explanation:

We are given that dragon costume have triangular spikes down the head and back.

The area of triangular shape is given by

Area = ½×b×h

Where b is the base and h is the height

The area of the head spike is

A₁ = ½×b₁×h₁

A₁ = ½×2×6

A₁ = ½×12

A₁ = 6 cm²

But we know that the number of head spikes is 16 so the total area of the head spikes is

A₁ = 16×6

A₁ = 96 cm²

The area of the back spike is

A₂ = ½×b₂×h₂

A₂ = ½×6×10

A₂ = ½×60

A₂ = 30 cm²

But we know that the number of back spikes is 6 so the total area of the back spikes is

A₂ = 6×30

A₂ = 180 cm²

The total area required is the sum of the area of head spikes and back spikes,

Total area = A₁ + A₂

Total area = 96 + 180

Total area = 276 cm²

Therefore, Farrah would need 276 cm² of fabric for all the dragon spikes.

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Solve using substitution
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