The answer I got was 280 calories. I got that by dividing 200 by 50. Which I then got 4. Then, I multiplied 4 by 70 yo get 280 calories.
Answer:
87.4%
Step-by-step explanation:
The radius to the top of the atmosphere as a fraction of the moon's radius is ...
(2575 +600)/2575 ≈ 1.23301
The ratio of the moon's volume with atmosphere to the moon's volume without is the cube of this, or 1.87456
Then the ratio of the atmosphere's volume to the moon's volume is ...
(1.87456 -1)/1 = 0.87456
Atmospheric haze is about 87.4% of the moon's volume.
_____
We have assumed that the desired ratio is to the solid moon's volume, not the volume of moon and atmosphere together. The latter ratio would be 0.875 to 1.875 or about 46.7%.
There is actually no one ☝
We have been given an equation of hyperbola 
. We are asked to find the center of hyperbola.
We know that standard equation of a vertical hyperbola is in form 
, where point (h,k) represents center of hyperbola.
Upon comparing our given equation with standard vertical hyperbola, we can see that the value of h is 6.
To find the value of k, we need to rewrite our equation as:
Now we can see that value of k is 
. Therefore, the vertex of given hyperbola will be at point 
and option D is the correct choice.
