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2 years ago

Plzz help i don't understand that well

Mathematics

2 answers:

katrin2010 [14]2 years ago

4 0

Answer:

It can't

Step-by-step explanation:

The widest that the third side could be if 6 and 5 are the other sides would be 11 but 14>11

postnew [5]2 years ago

3 0

Answer:

Step-by-step explanation:

A triangle's lengths HAVE TO add up to 180 degrees.

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Eliminate the parameter. x = t2 + 2, y = t2 - 4

stepan [7]

$\bf \begin{cases}
x=t^2+2\implies x-2=t^2\implies \sqrt{x-2}=\boxed{t}\\\\
y=t^2-4\\
----------\\
y=\left( \boxed{\sqrt{x-2}} \right)^2-4\implies y=x-2-4\\\\
y=x-6
\end{cases}$

just a plain vanilla substitution

8 0

3 years ago

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Please help asap!!!!

oksian1 [2.3K]

Answer:

144

Step-by-step explanation:

Length of 1 side is 12 so area is 12*12

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3 years ago

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the area of a square can be quadrupled by increasing the side length and width by 4 inches. what is the side length?

Semmy [17]

The number could be anything because whatever it is it can be quadrupled

3 0

2 years ago

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Simplify 2^3 • 2^7<br><br> answer quick pls lol

yarga [219]

Answer:

It's A.

Step-by-step explanation:

2^3 •2^7 = 1024

2^10 = 1024

3 0

2 years ago

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Please help, and thank you!

lawyer [7]

Answer:

3. C

4. D

Step-by-step explanation:

$x^2+25=0\\x^2=-25\\x=\pm\sqrt{-25}$

Once $\sqrt{-1}=i$

$x=\pm5i$

A quadratic equation has no real roots when the discriminant ( $\Delta$ ) is negative. $\Delta$ .

Let's try all the equations:

(A)

$2x^2-7x-9=0\\\\\Delta=\sqrt{\left(-7\right)^2-4\cdot \:2\left(-9\right)}\\\Delta=\sqrt{\left(-7\right)^2+4\cdot \:2\cdot \:9}\\\Delta=\sqrt{121} \\\Delta=11$

(B)

$2x^2=7x\\2x^2-7x=0\\x(2x-7)=0\\x=0\\\text{or}\\2x-7=0\\2x=7\\\\$

$x=\frac{7}{2}$

(C)

$2x^2+7x-9=0\\\Delta = \sqrt{7^2-4\cdot \:2\left(-9\right)}\\\Delta = \sqrt{7^2+4\cdot \:2\cdot \:9}\\\Delta = \sqrt{121} \\\Delta= 11$

(D)

$2x^2-7x+9=0\\\Delta = \sqrt{\left(-7\right)^2-4\cdot \:2\cdot \:9}\\\\\Delta=\sqrt{-23} \\\Delta=\sqrt{23i}$

8 0

2 years ago