Tan ( a + b ) = [ tan a + tan b ] / [ 1 - (tan a)*(tan b) ];
let be a = 2x and b = x;
=> tan 3x = [ tan 2x + tan x ] / [ 1 - (tan 2x)*(tan x) ] => (tan 3x)*[ 1 - (tan 2x)*(tan x) ] =
tan 2x + tan x => tan3x - tan 3xtan 2xtanx = tan 2x + tan x => <span> tan 3x−tan 2x−tanx = tan 3xtan 2xtanx.</span><span />
3 1/3 times 2 1/2 =3 2/6 times 2 3/6 =6 15/6=8 3/6
8 3/6 I THINK
Answer: -750ft
Step-by-step explanation: -450+-300=-750
Answer:
-5/9 and -1
Step-by-step explanation:
1. to differentiate the given function; 2. to substitute the coordinates of the point.
Answer: 14
Step-by-step explanation:
Given
Excavation cone measures
height 
Diameter 
Truck can dump
at a time
The volume of a cone is

Putting values

No of trips(N) required to accumulate this much volume is given by

Therefore, 14 trips are necessary to accumulate a cone of volume 