A survey asked 10 boys and 10 girls how many text messages they sent the previous day. The

Bored anyone wanna talk? or do a zo om?

Serga [27]

Answer:

Step-by-step explanation:

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⣿⣿⣿⣿⣿⡏⠉⠛⢿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⡿⣿

⣿⣿⣿⣿⣿⣿⠀⠀⠀⠈⠛⢿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⠿⠛⠉⠁⠀⣿

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LOL

3 0

2 years ago

Read 2 more answers

Determine whether the value is a discrete random variable, continuous random variable, or not a random variable. a. The number

Fiesta28 [93]

Answer:

Discrete variables are those whose distribution will only take a finite number of values which are represented by integer values only.

Continous variables on the other hand could have an infinite number of points inbetween two integer values. With the values inbetween being decimals.

Step-by-step explanation:

a. The number of textbook authors now sitting at a computer :

A discrete random variable

Number of authors will be an integer value.

b. The height of a randomly selected giraffe ;

Continous random variable

Possible height value : h > 0

c. The responce to the survey question "Did you smoke in the last week"

It is not a random Variable

The response isn't numeric

d. The amount of rain in City B during April

It is a continous random variable

Possible values ; amount of rain > 0

e. The time it takes to fly from City A to City B

It is a continous random variable

Time could take up seconds value ;

Possible values : t > 0

f. The number of light bulbs that burn out in the text week in a room with 17 bulbs

It is a discrete random variable

Number of bulbs is defined

6 0

3 years ago

Two intersecting lines have ______ of point(s) in common.

Vladimir79 [104]

They only have 1 common point

5 0

3 years ago

Read 2 more answers

29/24 simplified help pls

mote1985 [20]

Decimal- 1.2083…
Mixed number- 1 5/24

3 0

3 years ago

Read 2 more answers

Please see attachment

Dafna11 [192]

Answer:

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

Step-by-step explanation:

Step(i):-

Given function

$f(x) = \frac{-x}{2x^{2} +1}$ ...(i)

Differentiating equation (i) with respective to 'x'

$f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2} }$ ...(ii)

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} }$

Equating Zero

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$\frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$2 x^{2}-1 = 0$

$2 x^{2} = 1$

$x^{2} = \frac{1}{2}$

$x = \frac{-1}{\sqrt{2} } , x = \frac{1}{\sqrt{2} }$

Step(ii):-

Again Differentiating equation (ii) with respective to 'x'

$f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4} }$

put

$x = \frac{1}{\sqrt{2} }$

$f^{ll} (x) > 0$

The absolute minimum value at $x = \frac{1}{\sqrt{2} }$

Step(iii):-

The value of absolute minimum value

$f(x) = \frac{-x}{2x^{2} +1}$

$f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}$

on calculation we get

The value of absolute minimum value = - 0.3536

Final answer:-

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

3 0

3 years ago