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otez555 [7]
3 years ago
11

I need help please and thank you.

Mathematics
1 answer:
Zinaida [17]3 years ago
7 0

Answer:

0

Step-by-step explanation:

The formula gives you a relation between S and n. For every n, you can perform the calculation and obtain an S.

So, for n=0 we get 0/2 (0+1) which equals 0. So (0,0) is an (n,S) pair.

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What is the Volume?
Serhud [2]

Answer:

703.36

Step-by-step explanation:

the formula is v=b×h×pi

pi = 3.14

length: 28

base:8

So base (8) times length (28) times pi (3.14)

8×28×3.14 = 703.36

8 0
2 years ago
Identify the angle relationship, write an equation and Solve for x. ​
irakobra [83]

Answer:

2x-6+x+x=180

4x-6=180

4x=180+6

4x=186

x=\frac{186}{4}=46,5°

Step-by-step explanation: the other angle is equal to his simmetrical, cause the triangle is isosceles, so is value is x. The sum of the angle in a triangle must be 180°

6 0
3 years ago
What is the solution to the equation 9(x − 1) = 27? (1 point) x = 2.5 x = 0.5 x = −0.5 x = −3.5
Tems11 [23]

Step-by-step explanation:

Are you sure you wrote the answers correctly?

7 0
3 years ago
Read 2 more answers
If i= square root of -1, what is the value of i^3
Ber [7]

Answer:

- i

Step-by-step explanation:

Set up equation.

i {}^{3}  = y

{i}^{2 }  \times i = y

- 1 \times i = y

- i = y

6 0
3 years ago
Health insurers are beginning to offer telemedicine services online that replace the common office visit. A company provides a v
Veronika [31]

Answer:

\text {CI} = (60.54, \: 81.46)\\\\

Therefore, we are 95% confident that actual mean savings for a televisit to the doctor is within the interval of ($60.54 to $81.46)

Step-by-step explanation:

Let us find out the mean savings for a televisit to the doctor from the given data.

Using Excel,

=AVERAGE(number1, number2,....)

The mean is found to be

\bar{x} = \$71  

Let us find out the standard deviation of savings for a televisit to the doctor from the given data.

Using Excel,

=STDEV(number1, number2,....)

The standard deviation is found to be

 s = \$ 22.35

The confidence interval is given by

\text {confidence interval} = \bar{x} \pm MoE\\\\

Where the margin of error is given by

$ MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $ \\\\

Where n is the sample of 20 online doctor visits, s is the sample standard deviation and t_{\alpha/2} is the t-score corresponding to a 95% confidence level.

The t-score is given by is

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025

Degree of freedom = n - 1 = 20 - 1 = 19

From the t-table at α = 0.025 and DoF = 19

t-score = 2.093

So, the margin of error is

MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\MoE = 2.093\cdot \frac{22.35}{\sqrt{20} } \\\\MoE = 2.093\cdot 4.997\\\\MoE = 10.46\\\\

So the required 95% confidence interval is

\text {CI} = \bar{x} \pm MoE\\\\\text {CI} = 71 \pm 10.46\\\\\text {CI} = 71 - 10.46, \: 71 + 10.46\\\\\text {CI} = (60.54, \: 81.46)\\\\

Therefore, we are 95% confident that actual mean savings for a televisit to the doctor is within the interval of ($60.54 to $81.46)

7 0
3 years ago
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