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valentinak56 [21]
3 years ago
9

Please help me on this!!

Physics
2 answers:
Katarina [22]3 years ago
8 0
B or A ima go with B
dexar [7]3 years ago
5 0
I would say b or a but b is a more reasonable answer
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4vir4ik [10]
It brings cold water from the bottom of the ocean.
4 0
3 years ago
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A golf club rotates 215 degrees and has a length (radius) equal to 29 inches. The time it took to swing the club was 0.8 seconds
vichka [17]

Answer:

The average linear velocity (inches/second) of the golf club is 136.01 inches/second

Explanation:

Given;

length of the club, L = 29 inches

rotation angle, θ = 215⁰

time of motion, t = 0.8 s

The angular speed of the club is calculated as follows;

\omega = (\frac{\theta}{360} \times 2\pi, \ rad) \times \frac{1}{t} \\\\\omega =  (\frac{215}{360} \times 2\pi, \ rad) \times \frac{1}{0.8 \ s} \\\\\omega = 4.69 \ rad/s

The average linear velocity (inches/second) of the golf club is calculated as;

v = ωr

v = 4.69 rad/s  x  29 inches

v = 136.01 inches/second

Therefore, the average linear velocity (inches/second) of the golf club is 136.01 inches/second

8 0
3 years ago
The coefficient of static friction between car's tires and a level road is 0.80 If car to be stopped in time of 3.0 sec its spee
Vlad1618 [11]

Answer:

23.5 m/s

Explanation:

The velocity of the car in decelerated motion is given by

v = u + at

where

v = 0 is the final velocity

u is the initial velocity

a is the acceleration of the car

t = 3.0 s is the time it takes for the car to stop

The acceleration of the car is given by the frictional force, which is the only force acting on the car along the direction of motion, so:

ma = -\mu mg\\a = -\mu g = -(0.80)(9.8 m/s^2)=-7.84 m/s^2

where

\mu=0.80 is the coefficient of friction

Solving the previous equation for u, we find the initial velocity:

u=v-at=0-(-7.84 m/s^2)(3.0 s)=23.5 m/s

4 0
4 years ago
What qualifications do you need to be a research scientist?
Vedmedyk [2.9K]

The qualifications boil down to: College education.

In most university or industrial research organizations, you might be able to work there as a member of the team who doesn't get much pay or much respect, with research going on all around you directed by other people, after you've gotten you Master's degree.

But you really don't have a shot at leading anything, or having much to say about what's being researched or how, until you have a PhD degree in the field where you'd like to do the research.

(Did I mention how proud I was to be present about 6 weeks ago, in a land far away, when my daughter was awarded a PhD degree in Molecular Biology ? I didn't want to let you get away without hearing about that.)

5 0
3 years ago
The index of refraction of silicate flint glass for red light is 1.620 and for violet light is 1.660 . A beam of white light in
chubhunter [2.5K]

Answer:

The angular separation equals 0.35^{o}

Explanation:

We have according to Snell's law

n_{1}sin(\theta _{1})=n_{2}sin(\theta _{2})

\therefore \theta _{2}=sin^{-1}(\frac{n_{1}sin(\theta _{1})}{n_{2}})

Using this equation for both the colors separately we have

\theta _{red}=sin^{-1}(\frac{sin(23.90^{o})}{1.62})\\\\\theta _{red}=14.48^{o}

Similarly for violet light we have

\theta _{violet}=sin^{-1}(\frac{sin(23.90^{o})}{1.660})\\\\\theta _{violet}=14.13^{o}

Thus the angular separation becomes

\Delta \theta =14.48-14.13=0.35^{o}

6 0
4 years ago
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