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miv72 [106K]
3 years ago
12

What are prime numbers ? And a list of examples ?

Mathematics
1 answer:
Helga [31]3 years ago
7 0

Answer:

the number which is divisible only by itself and 1 is called prime number. For example; 2,3, 5, 7, 11 and others.

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Find the area of the figure.
Slav-nsk [51]

Answer:

132cm

Step-by-step explanation:

Split there firgue into shapes you know

there is a rectangle and a Trapezoid

A = bh

A = 7×4

A = 28cm

Trapezoid

A = 1/2h(b+b)

A = 1/2×8(19+7)

A = 1/2×8(26)

A = 1/2(208)

A = 104cm

Add them together

104 + 28 = 132

4 0
3 years ago
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How do you find the r?
Margarita [4]
By finding the volume of the shape
6 0
3 years ago
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Someone, please help my teacher doesn't want to help me and ugh I'm frustrated. Any help would be great!
maw [93]

Answer:

my brother said it is 5 and 10... but i do not know if it is

7 0
2 years ago
( Will give Brainlies) Please Helpp
mario62 [17]

Answer:

15 or below

Step-by-step explanation:

10+10+8+8 = 36

51-36 = 15

Less than or equal to = 15 or below

4 0
3 years ago
Debra plans to invest $2,250 for 10 years. She can invest in a savings account that pays 4% simple intrest or a savings account
Diano4ka-milaya [45]

Answer:

\$180.55

Step-by-step explanation:

step 1

<u><em>Simple interest</em></u>

we know that

The simple interest formula is equal to

A=P(1+rt)

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

t=10\ years\\ P=\$2,250\\r=4\%=4/100=0.04

substitute in the formula above

A=2,250(1+0.04*10)

A=2,250(1.4)

A=\$3,150

step 2

<u><em>Interest compounded annually</em></u>

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=10\ years\\ P=\$2,250\\r=4\%=4/100=0.04\\n=1

substitute in the formula above

A=2,250(1+\frac{0.04}{1})^{1*10}  

A=2,250(1.04)^{10}  

A=\$3,330.55

step 3

Find the differences between the two final amounts

A=\$3,330.55-\$3,150=\$180.55

5 0
3 years ago
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