Question 6

Q. During one particular sales day, 75% of the store's customers

serious [3.7K]

60-75%= 45
So 60-45=15
15 people used credit cards

4 0

3 years ago

Directions : Factor each of the following Differences of two squares and write your answer together with solution

N76 [4]

$\huge \boxed{\mathfrak{Question} \downarrow}$

Factor each of the following differences of two squares and write your answer together with solution.

$\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}$

$\sf \: x ^ { 2 } - 36$

Rewrite $\sf\:x^{2}-36 as x^{2}-6^{2}$ . The difference of squares can be factored using the rule: $\sf\: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right)$ .

$\boxed{ \boxed{ \bf\left(x-6\right)\left(x+6\right) }}$

__________________

$\sf \: 49 - x ^ { 2 }$

Rewrite 49-x² as 7²-x². The difference of squares can be factored using the rule: $\sf\:a^{2}-b^{2}=\left(a-b\right)\left(a+b\right)$ .

$\sf \: \left(7-x\right)\left(7+x\right)$

Reorder the terms.

$\boxed{ \boxed{ \bf\left(-x+7\right)\left(x+7\right) }}$

__________________

$\sf \: 81 - c ^ { 2 }$

Rewrite 81-c²as 9²-c². The difference of squares can be factored using the rule: $\sf\:a^{2}-b^{2}=\left(a-b\right)\left(a+b\right)$ .

$\sf\left(9-c\right)\left(9+c\right)$

Reorder the terms.

$\boxed{ \boxed{ \bf\left(-c+9\right)\left(c+9\right) }}$

__________________

$\sf \: m ^ { 2 } n ^ { 2 } - 1$

Rewrite m²n² - 1 as $\sf\left(mn\right)^{2}-1^{2}$ . The difference of squares can be factored using the rule: $\sf\:a^{2}-b^{2}=\left(a-b\right)\left(a+b\right)$ .

$\boxed{ \boxed{ \bf\left(mn-1\right)\left(mn+1\right) }}$

4 0

3 years ago

Read 2 more answers

On February 1, the electricity meter reading for the Smith residence was 19,423 kilowatt hours. On March 1, the meter read 20,28

Karolina [17]

A. How many kilowatt hours of electricity did the Smiths use during February?

Kilowatt hours of electricity the Smiths used during February:
Meter read on March 1 - meter read on February 1 =
20,288 kilowatt hours - 19,423 kilowatt hours =
865 kilowatt hours
Answer: The Smiths used 865 kilowatt hours of electricity during February

b. How many kilowatt hours did they use during March?

Kilowatt hours of electricity the Smiths used during March:
Meter read on April 1 - meter read on March 1 =
21,163 kilowatt hours - 20,288 kilowatt hours =
875 kilowatt hours
Answer: The Smiths used 875 kilowatt hours of electricity during March

8 0

3 years ago

plz hurry 82 points help plzThe rental rate for a power washer has a one time fee of $50 plus $25 for each day of the rental. Th

Sveta_85 [38]

Answer: y = 25x + 50

Explanation: the total cost if the rental is a linear function of the number of days of the rental (x). Each day costs $25, so that is the slope of the line. Since there is also a one-time fee, independent of the number of days, this amount $50 represents a vertical shift of the line on the graph, by 50. y=25x+50 is an algebraic expression of that.

6 0

3 years ago

Read 2 more answers

Find the measures of the angles given

dexar [7]

Answer:

BCD = 60

ABD - 90

Step-by-step explanation:

BCD)

BC and CD are the same length on in the circle, they are the radius. Therefor, all angles will be the same at 60

ABD)

All angles together are 180

You know 2 Angles, A at 30 and D at 60

180 - 30 - 60 = Angle B

90 = Angle B

6 0

3 years ago