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kakasveta [241]

3 years ago

8

I'm very confused on what the answer to this one is

2 answers:

Natasha2012 [34]3 years ago

7 0

P (-6, 3) Q(0, 6) R (6,6)

Vikentia [17]3 years ago

6 0

Answer:

(-3,1.5) (0,3) (3'3)

Step-by-step explanation:

multiply all the coordinates by 1/2

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Directions: Find the indicated trigonometric ratio as a fraction in simplest form. 1. Sin L =

Rainbow [258]

Answer:

$\sin L = 0.60$

$tan\ N = 1.33$

$\cos L = 0.80$

$\sin N = 0.80$

Step-by-step explanation:

Given

See attachment

From the attachment, we have:

$MN = 6$

$LN = 10$

First, we need to calculate length LM,

Using Pythagoras theorem:

$LN^2 = MN^2 + LM^2$

$10^2 = 6^2 + LM^2$

$100 = 36 + LM^2$

Collect Like Terms

$LM^2 = 100 - 36$

$LM^2 = 64$

$LM = 8$

Solving (a): $\sin L$

$\sin L = \frac{Opposite}{Hypotenuse}$

$\sin L = \frac{MN}{LN}$

Substitute values for MN and LN

$\sin L = \frac{6}{10}$

$\sin L = 0.60$

Solving (b): $tan\ N$

$tan\ N = \frac{Opposite}{Adjacent}$

$tan\ N = \frac{LM}{MN}$

Substitute values for LM and MN

$tan\ N = \frac{8}{6}$

$tan\ N = 1.33$

Solving (c): $\cos L$

$\cos L = \frac{Adjacent}{Hypotenuse}$

$\cos L = \frac{LM}{LN}$

Substitute values for LN and LM

$\cos L = \frac{8}{10}$

$\cos L = 0.80$

Solving (d): $\sin N$

$\sin N = \frac{Opposite}{Hypotenuse}$

$\sin N = \frac{LM}{LN}$

Substitute values for LM and LN

$\sin N = \frac{8}{10}$

$\sin N = 0.80$

7 0

3 years ago

Please help me with my math

ValentinkaMS [17]

Im failing math but passing all others im sorry lol

7 0

3 years ago

A little help here ^-^

vovangra [49]

I think the answer is 50

3 0

3 years ago

Read 2 more answers

Solve b to the second power=77

zubka84 [21]

Answer:

$\large\boxed{b=\pm\sqrt{77}}$

Step-by-step explanation:

$b^2=77\iff b=\pm\sqrt{77}\\\\\text{because}\\\\(-\sqrt{77})^2=77\ \text{and} \ (\sqrt{77})^2=77$

3 0

3 years ago

A street lamp is 14 ft tall. On a sunny day, the street lamp casts a shadow 8 ft long. What is

saw5 [17]

Answer:

60.25≈60.3°

Step-by-step explanation:

tanФ=14/8=1.75

Ф=arctan=1.75

tan-1

60.25≈60.3

8 0

3 years ago