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3 years ago

Write an equation of the line that passes through (2 -5) and is parallel to the line 2y=3x+10

Mathematics

1 answer:

andrey2020 [161]3 years ago

8 0

Step-by-step explanation:

Given equation is

2y = 3x + 10

3x - 2y + 10 = 0 .....i)

Any line parallel to line I) is

3x - 2y + k = 0 ......ii)

As the line two passes through the point ( 2 , - 5 ) Now substituting the values

3 * 2 - 2 * ( - 5) + k = 0

6 + 10 + k = 0

16 + k = 0

k = - 16

Now putting the value of k in equation two

3x - 2y + 16 = 0 is the required equation.

Hope it will help :)❤

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Point A is (5, 7).

spin [16.1K]

The coordinate of point B is at (29, -15): Option C is correct.

The formula for calculating the midpoint of two points is expressed as:

$M(x, y) = {\frac{x_2+x_1}{2}, \frac{y_2+y_1}{2}}$

Given the coordinate points

A is (5, 7).

B is (x, y).

M is (17, -4)

Substituting into the formula to get x and y

17 = 5+x/2

5+x = 34

x = 34 - 5

x = 29

Get the value of y. Similarly;

-4 = 7+y/2

-8 = 7+y

y = -8-7

y = -15

Hence the coordinate of point B is at (29, -15)

Learn more here: brainly.com/question/13989426

5 0

2 years ago

Find the surface area of the ball shown to the right <br><br> d=20

netineya [11]

Answer:

<h3>Surface Area = 1,256 cm</h3>

<u>Solution:</u>

formula: Surface Area of a Sphere: 4π · r²

Surface area = 4π · r²

SA = 4(3.14) (10)²

SA = (12.56)(100)

SA = 1,256

7 0

2 years ago

I Need Help With 9 And 10Please Help

Burka [1]

9: the answer is 4 to 13
10: the answer is 6 to 13

5 0

3 years ago

The prices of all college textbooks follow a bell-shaped distribution with a mean of $113 and a standard deviation of $12. Using

Soloha48 [4]

Step-by-step explanation:

In statistics, the empirical rule states that for a normally distributed random variable,

68.27% of the data lies within one standard deviation of the mean.

95.45% of the data lies within two standard deviations of the mean.

99.73% of the data lies within three standard deviations of the mean.

In mathematical notation, as shown in the figure below (for a standard normal distribution), the empirical rule is described as

$\Phi(\mu \ - \ \sigma \ \leq X \ \leq \mu \ + \ \sigma) \ = \ 0.6827 \qquad (4 \ \text{s.f.}) \\ \\ \\ \Phi(\mu \ - \ 2\sigma \ \leq X \ \leq \mu \ + \ 2\sigma) \ = \ 0.9545 \qquad (4 \ \text{s.f.}) \\ \\ \\ \Phi}(\mu \ - \ 3\sigma \ \leq X \ \leq \mu \ + \ 3\sigma) \ = \ 0.9973 \qquad (4 \ \text{s.f.})$

where the symbol $\Phi$ (the uppercase greek alphabet phi) is the cumulative density function of the normal distribution, $\mu$ is the mean and $\sigma$ is the standard deviation of the normal distribution defined as $N(\mu, \ \sigma)$ .

According to the empirical rule stated above, the interval that contains the prices of 99.7% of college textbooks for a normal distribution $N(113, \ 12)$ ,

$\Phi(113 \ - \ 3 \ \times \ 12 \ \leq \ X \ \leq \ 113 \ + \ 3 \ \times \ 12) \ = \ 0.9973 \\ \\ \\ \-\hspace{1.75cm} \Phi(113 \ - \ 36 \ \leq \ X \ \leq \ 113 \ + \ 36) \ = \ 0.9973 \\ \\ \\ \-\hspace{3.95cm} \Phi(77 \ \leq \ X \ \leq \ 149) \ = \ 0.9973$

Therefore, the price of 99.7% of college textbooks falls inclusively between $77 and $149.

5 0

2 years ago

I’ve been stuck on this question for an hour? I need help ASAP! Thanks! What is the total surface area of the trapezoidal prism?

CaHeK987 [17]

Answer:

262mmsq

Step-by-step explanation:

7 0

3 years ago