The formula for area of a square is s^2 so it would be 7; the perimeter would be 7+7+7+7= 28 and the area would be 7^2= 49
Answer:
(a)
Area: 930 meters(m)
Perimeter: 122 meters(m)
(b)
Area: 616 centimeters(cm)
Perimeter: 116 centimeters(cm)
(c)
Area: 1008 millimeters(mm)
Perimeter: 128 millimeters(mm)
Explanation:
Area = length x width
Perimeter = length+width+length+width
Area for (a) is then 31 times 30 = 930
Area for (b) is then 44 times 14 = 616
Area for (c) is then 36 times 28 = 1008
Perimeter for (a) is 31+30+31+30=122
Perimeter for (b) is 44+14+44+14=116
Perimeter for (c) is 36+28+36+28=128
Answer:201 in squared
Step-by-step explanation:
a right circular cone has
a diameter d=8+in ...........r=4+in
a height of h=12+in
the volume
the vomue 1/3 times pie times r squared times height
the vlolume 1/3 times pie times 4 in squared times 12in
the vlolume 1/3 times pie times 16 in squared times 12 in
the vlolume 192 times pie inches squared over 3
the vlolume 200.96 in squared
whcih should equal 201 inches squared.
Answer:
Given the expression: ![3y^3-2y[4y-y(y-3)]-[2y(y+1)-3y(y^2-1)]](https://tex.z-dn.net/?f=3y%5E3-2y%5B4y-y%28y-3%29%5D-%5B2y%28y%2B1%29-3y%28y%5E2-1%29%5D)
The distributive property says that:
Applying distributive property on the given expression, we have;
![3y^3-2y[4y-y^2+3y]-[2y^2+2y-3y^3+3y]](https://tex.z-dn.net/?f=3y%5E3-2y%5B4y-y%5E2%2B3y%5D-%5B2y%5E2%2B2y-3y%5E3%2B3y%5D)
again apply the same property we have
![3y^3-8y^2+2y^3-6y^2-[2y^2+2y-3y^3+3y]](https://tex.z-dn.net/?f=3y%5E3-8y%5E2%2B2y%5E3-6y%5E2-%5B2y%5E2%2B2y-3y%5E3%2B3y%5D)
or
Like terms are those terms which have same variables to the same power.
Combine like terms;
Therefore, the simplified form of the given expression is,
