The complete question is
A school purchases boxes of candy bars.
<span>• Each box contains 50 candy bars. </span>
<span>• Each box costs $30. </span>
<span>How much does the school have to charge for each candy bar to make a profit of </span>
<span>$10 per box?
</span>
step 1
charge for each box $10
so
the new box cost $10+$30=$40
step 2
divide the new box cost to total candy bars
$40/50=$0.80
the answer is
the school have to charge for each candy bar $0.80
There aren't any "following" equations, but I can give you one nonetheless.
y = 91 + 5x
This is because 91 is the minimum and y-intercept, x is each individual box, and the 5 is $5 per box.
Hope this helps!
This regular polygon, having eight sides and 45º angle in similar parts, when rotating 360º, will find a similar image and a similar angle of 45º, therefore dividing the angle of 360º by 45º will be the Number of coincidences<span> in image.
</span><span>Solving, thus, we have:
</span>
![\frac{360}{45} = \boxed{\boxed{8\:coincidences\:in\:image}}\end{array}}\qquad\quad\checkmark](https://tex.z-dn.net/?f=%20%5Cfrac%7B360%7D%7B45%7D%20%3D%20%5Cboxed%7B%5Cboxed%7B8%5C%3Acoincidences%5C%3Ain%5C%3Aimage%7D%7D%5Cend%7Barray%7D%7D%5Cqquad%5Cquad%5Ccheckmark)
<span>
</span>
Answer:
and ![m\angle CAB=119^{\circ}](https://tex.z-dn.net/?f=m%5Cangle%20CAB%3D119%5E%7B%5Ccirc%7D)
Step-by-step explanation:
It is given that ![m\angle CAE=m\angle FAB =61^{\circ}](https://tex.z-dn.net/?f=m%5Cangle%20CAE%3Dm%5Cangle%20FAB%20%3D61%5E%7B%5Ccirc%7D)
and ![m\angle DAF=90^{\circ}](https://tex.z-dn.net/?f=m%5Cangle%20DAF%3D90%5E%7B%5Ccirc%7D)
To find: ![m\angle EAD\ and\ m\angle CAB](https://tex.z-dn.net/?f=m%5Cangle%20EAD%5C%20and%5C%20m%5Cangle%20CAB)
Now, since Line CAF and EAB intersect each other therefore,
(vertically opposite angles are equal) ...(1)
Now,
(Sum of linear pair)
![m\angle CAB= 180 ^{\circ}-m\angle EAC](https://tex.z-dn.net/?f=m%5Cangle%20CAB%3D%20180%20%5E%7B%5Ccirc%7D-m%5Cangle%20EAC)
![m\angle CAB= 180 ^{\circ} -61^{\circ}=119^{\circ}](https://tex.z-dn.net/?f=m%5Cangle%20CAB%3D%20180%20%5E%7B%5Ccirc%7D%20-61%5E%7B%5Ccirc%7D%3D119%5E%7B%5Ccirc%7D)
Now From eq. (1)
(vertically opposite angles are equal)
![m\angle EAF= m\angle EAD+m\angle DAF](https://tex.z-dn.net/?f=m%5Cangle%20EAF%3D%20m%5Cangle%20EAD%2Bm%5Cangle%20DAF)
![m\angle EAD= m\angle EAF-m\angle DAF](https://tex.z-dn.net/?f=m%5Cangle%20EAD%3D%20m%5Cangle%20EAF-m%5Cangle%20DAF)
![m\angle EAD= 119^{\circ}-90^{\circ}=29^{\circ}](https://tex.z-dn.net/?f=m%5Cangle%20EAD%3D%20119%5E%7B%5Ccirc%7D-90%5E%7B%5Ccirc%7D%3D29%5E%7B%5Ccirc%7D)
Answer:6
Step-by-step explanation: