Answer: WHAT
Step-by-step explanation:
A.
Coefficient: 50
Variable: h
Constant: s
b.
50(25) + 0.20(300) + 40
1250 + 60 + 40
1350
Corinne earns $1350
c.
The coefficient would change because a coefficient is the number in front of a variable, and the number changed, not the variable or constant.
Count how many times you have to move the decimal point to move it past the first number. in this case 6, so...
1.84*10^-6 is the answer.
Hope this helps! :)
Answer:
B. 1 out of 5,005
Step-by-step explanation:
Given
Number of Friends = 15
Required
Probability of selecting 6 friends
The first step is to calculate the number of ways 6 friends can be selected
The keyword in the above statement is selection;
This implies combination;
The number of ways is calculated as follows;
![\left[\begin{array}{c}n&r&\end{array}\right] = \frac{n!}{(n-r)!r!}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dn%26r%26%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7Bn%21%7D%7B%28n-r%29%21r%21%7D)
Where n = 15 and r = 6
![\left[\begin{array}{c}n&r&\end{array}\right] = \frac{n!}{(n-r)!r!}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dn%26r%26%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7Bn%21%7D%7B%28n-r%29%21r%21%7D)
becomes
![\left[\begin{array}{c}15&6&\end{array}\right] = \frac{15!}{(15-6)!6!}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D15%266%26%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7B15%21%7D%7B%2815-6%29%216%21%7D)
![\left[\begin{array}{c}15&6&\end{array}\right] = \frac{15!}{9!6!}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D15%266%26%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7B15%21%7D%7B9%216%21%7D)
![\left[\begin{array}{c}15&6&\end{array}\right] = \frac{15 * 14 * 13 * 12 * 11 *10 * 9!}{9! *6 * 5 * 4 * 3 * 2 * 1}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D15%266%26%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7B15%20%2A%2014%20%2A%2013%20%2A%2012%20%2A%2011%20%2A10%20%2A%209%21%7D%7B9%21%20%2A6%20%2A%205%20%2A%204%20%2A%203%20%2A%202%20%2A%201%7D)
![\left[\begin{array}{c}15&6&\end{array}\right] = \frac{15 * 14 * 13 * 12 * 11 *10}{6 * 5 * 4 * 3 * 2 * 1}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D15%266%26%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7B15%20%2A%2014%20%2A%2013%20%2A%2012%20%2A%2011%20%2A10%7D%7B6%20%2A%205%20%2A%204%20%2A%203%20%2A%202%20%2A%201%7D)
![\left[\begin{array}{c}15&6&\end{array}\right] = \frac{3603600}{720}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D15%266%26%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7B3603600%7D%7B720%7D)
![\left[\begin{array}{c}15&6&\end{array}\right] =5005](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D15%266%26%5Cend%7Barray%7D%5Cright%5D%20%3D5005)
Hence, there are 5005 ways of selecting 6 from 15 friends
Since, there's only one way of selecting the 6 named friends
Then, the probability is 1 out of 5,005
14 - 6 = 8 this is the answer