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VladimirAG [237]
3 years ago
9

How to solve monomials

Mathematics
1 answer:
rewona [7]3 years ago
8 0
You can't solvd monomials because they are just 1 term multiplication :
example: 2a , or 14
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8.5 x 250,000= 2125000
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Find the next term in the sequence 15 , 34 , 55 , 78 , 103
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The next term in the sequence will be increased by 27. The difference between 15 and 34 is 19 The difference between 34 and 55 is 21 The difference between 55 and 78 is 23 The difference between 78 and 103 is 25 Following this pattern, the next number will be 130

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2 years ago
The summit charges $4 fee and $3 per hour to rent a kayak. Extreme Paddling charges a $5 fee and $2 per hour to rent a kayak. Wr
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Answer:

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3 years ago
Please explain how to do this, I'm using all my points<br><br>A. 40 L<br>B. 80 L<br>C. 4 L <br>D. 8L
exis [7]

Answer: choice A. 40 liters

====================================

Explanation:

x = number of liters of the 50% alcohol solution

If we have x liters of 50% alcohol, then we have 0.50*x liters of pure alcohol. This is added to 0.90*40 = 36 liters of pure alcohol (from the 90% solution).

So far we have 0.50*x + 36. This expression represents the total amount of pure alcohol. We want a 70% solution, so we want 70% of the total 40+x meaning 0.50*x + 36 is to be set equal to 0.70*(40+x) and we solve for x as shown below

0.50*x + 36 = 0.70*(40+x)

0.50*x + 36 = 0.70*(40)+0.70*(x)

0.50*x + 36 = 28+0.70*x

36 - 28 = 0.70*x - 0.50x

8 = 0.20x

0.20x = 8

x = 8/0.20

x = 40

So that is why the answer is choice A. 40 liters

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2 years ago
Use the quadratic formula to solve for the roots of the following equation.<br> x 2 – 4x + 13 = 0
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With our equation, plug in the values:

x=\frac{4\pm \sqrt{(-4)^2-4*1*13}}{2*1}

Next, solve the exponent and multiplications:

x=\frac{4\pm \sqrt{16-52}}{2}

Next, solve the subtraction:

x=\frac{4\pm \sqrt{-36}}{2}

Next, factor out i (i = √-1):

x=\frac{4\pm \sqrt{36}i}{2}

Next, solve the square root:

x=\frac{4\pm 6i}{2}

Lastly, divide and <u>your answer is:</u>

x=2\pm 3i

5 0
3 years ago
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