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2 years ago

What is the term of the highest degree in the expression 3x2y-5xy7+8x4y5-6xy

Mathematics

1 answer:

skelet666 [1.2K]2 years ago

4 0

Answer:

seems hard

Step-by-step explanation:

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Write an equation for the vertical translation.

Lubov Fominskaja [6]

Answer:

y=-2/9 x – 9

Step-by-step explanation:

It really is simple translation because this is written in y=mx+b, where b is the given y-intercept. From there, just subtract what is needed to go down or add what is need to go up.

y=-2/9 x – 7 – 2

.:y=-2/9 x – 9

7 0

2 years ago

Determine the number of real solutions for each of the given equations. Equation Number of Solutions y = -3x2 + x + 12 y = 2x2 -

rosijanka [135]

Answer:

Step-by-step explanation:

Our equations are

$y = -3x^2 + x + 12\\y = 2x^2 - 6x + 5\\y = x^2 + 7x - 11\\y = -x^2 - 8x - 16\\$

Let us understand the term Discriminant of a quadratic equation and its properties

Discriminant is denoted by D and its formula is

$D=b^2-4ac\\$

Where

a= the coefficient of the $x^{2}$

b= the coefficient of $x$

c = constant term

Properties of D: If D

i) D=0 , One real root

ii) D>0 , Two real roots

iii) D<0 , no real root

Hence in the given quadratic equations , we will find the values of D Discriminant and evaluate our answer accordingly .

Let us start with

$y = -3x^2 + x + 12\\a=-3 , b =1 , c =12\\D=1^2-4*(-3)*(12)\\D=1+144\\D=145\\D>0 \\$

Hence we have two real roots for this equation.

$y = 2x^2 - 6x + 5\\$

$y = 2x^2 - 6x + 5\\a=2,b=-6,c=5\\D=(-6)^2-4*2*5\\D=36-40\\D=-4\\D$

Hence we do not have any real root for this quadratic

$y = x^2 + 7x - 11\\a=1,b=7,-11\\D=7^2-4*1*(-11)\\D=49+44\\D=93\\$

Hence D>0 and thus we have two real roots for this equation.

$y = -x^2 - 8x - 16\\a=-1,b=-8,c=-16\\D=(-8)^2-4*(-1)*(-16)\\D=64-64\\D=0\\$

Hence we have one real root to this quadratic equation.

7 0

2 years ago

Find the arithmetic and the geometric means of 5 and 125

nata0808 [166]

Answer: The geometric mean of 125 and 5 is 25

4 0

2 years ago

Read 2 more answers

100 pounds of chocolate is packaged into boxes each containing 1^1/4 pounds of chocolate. Each box is then sold for $1.75. What

sertanlavr [38]

Answer:

$140

Step-by-step explanation:

Total Amount of chocolate = 100 Pounds

Amount of chocolate in one box = 1 1/4 Pounds = 5/4 Pounds

Number of boxes = 100/(5/4) = 80 boxes

Cost of one box = $1.75

Total selling price = 80×1.75 = 140

The total selling price for all the boxes of chocolate is $140

8 0

2 years ago

Read 2 more answers

The graph shows the amount of water that remains in a barrel after it begins to leak. The variable x represents the number of da

vivado [14]

A = ( 15 , 15 )

B = ( 6 , 33 )

$slope = \frac{y(b) - y(a)}{x(b) - x(a)} \\$

$slope = \frac{33 - 15}{ 6 - 15} \\$

$slope = \frac{18}{ - 9} \\$

$slope = - 2$

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7 0

3 years ago