A semicircle is cut out of a rectangular paperboard 24in long and 18n wide, as shown below. What is the perimeter of the paperbo
ard that remains after the semicircle is removed? (Use the value 3.14 for π , and do not round your answer. Be sure to include the correct unit in your answer.)
1 answer:
Answer:
Perimeter of the paperboard that remains after the semicircle is removed = 94.26 in
Step-by-step explanation:
Watch the attached figure of how the semi circle is cut out of the rectangular paperboard.
Length = 24 in
Width = 18 in
Radius of the semi circle = Half of the width of the paperboard = = 9 in
1) Circumference of the semi circle = π*radius
= 3.14*9
= 28.26 in
2) Perimeter of the paperboard that remains after the semicircle is removed
= Top + Left + Bottom + Right Circumference of the semi circle
= 24 + 18 + 24 + 28.26
= 94.26 in
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Answer:
The incentive program does not cuts down on the number of days missed by employees.
Step-by-step explanation:
The dependent t-test (also known as the paired t-test or paired samples t-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.
A paired <em>t</em>-test would be used to determine whether the incentive program cuts down on the number of days missed by employees.
The hypothesis for the test can be defined as follows:
<em>H₀</em>: The incentive program does not cuts down on the number of days missed by employees, i.e. <em>d</em> ≥ 0.
<em>Hₐ</em>: The incentive program cuts down on the number of days missed by employees, i.e. <em>d</em> < 0.
From the information provided the data computed is as follows:
Compute the test statistic value as follows:
The test statistic value is -1.16.
Decision rule:
If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.
Compute the p-value of the test as follows:
*Use a t-table.
The p-value of the test is 0.1379.
The p-value of the test is very large for all the commonly used significance level. The null hypothesis will not be rejected.
Thus, there is not enough evidence to support the claim.
Conclusion:
The incentive program does not cuts down on the number of days missed by employees
