A semicircle is cut out of a rectangular paperboard 24in long and 18n wide, as shown below. What is the perimeter of the paperbo
ard that remains after the semicircle is removed? (Use the value 3.14 for π , and do not round your answer. Be sure to include the correct unit in your answer.)
1 answer:
Answer:
Perimeter of the paperboard that remains after the semicircle is removed = 94.26 in
Step-by-step explanation:
Watch the attached figure of how the semi circle is cut out of the rectangular paperboard.
Length = 24 in
Width = 18 in
Radius of the semi circle = Half of the width of the paperboard = = 9 in
1) Circumference of the semi circle = π*radius
= 3.14*9
= 28.26 in
2) Perimeter of the paperboard that remains after the semicircle is removed
= Top + Left + Bottom + Right Circumference of the semi circle
= 24 + 18 + 24 + 28.26
= 94.26 in
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Step-by-step explanation:
1) -9 = 9 true/false
the answer is false because negative and positive quite unlike in terms.
2) -(-21) = -21
Using the symbols multiplication rule,
Where,
<h2>+ × + = +</h2><h2>- × - = +</h2><h2>- × + = -</h2><h2>+ × - = -</h2>Therefore, -(-21) = +21 = 21
⟼ 21 = -21