Answer:
Step-by-step explanation: <u>Speed</u> is distance an object travelled per unit time.
It is represented by letter v and can assume various units.
1) 
v = 18 miles per hour
Her average speed is 18 mph.
2) Rearraging formula for distance:
d = v.t
d = 70 * 4
d = 280 miles
You would travel 280 miles.
3) 
v = 52.5 mph
My average speed is 52.5 mph.
4) Rearranging formula to determine time:
t = 2.34 hours
It will take 2 hours and half to arrive in Leeds. So, we will be expected to arrive at 12:04.
5) The unit change but the way of calculating time is the same.
t = 500 s
or t = 8.34 minutes
It will take, for an athlete to run 2000m, 8.34 minutes.
6) a) All units must match, so for a speed in mph:
45 minutes is 0.75 hours. Total time is 8.75 hours.
v = 560 mph
The average speed is 560 mph.
b)
t = 6.67 hours
Sam will take 6.67 hours to covered the distance.
F ( x ) = ( x + 3 )² - 8 = x² + 6 x + 9 - 8 = x² + 6 x + 1
For the quadratic function:
Axis of symmetry is: x = -b/ 2 a, where: a = 1, b = 6 ( because it it in the form:
y = a x² + b x + c ).
Therefore: x = -6 / 2 = -3.
f ( - 3 ) = ( - 3 + 3 )² - 8 = 0 - 8 = - 8
And D = b² - 4 a c = 6² - 4 * 1 * 1 = 36 - 4 = 32 ( greater than 0 ). It means that there are 2 real solutions.
Answer: x = - 3 , vertex : ( - 3 , - 8 ), Number of real solutions : 2.
a 1 = - 3 , a 2 = - 3 , a 3 = - 8 , a 4 = 2.
Answer:
y = -1/2x +11/2
Step-by-step explanation:
slope finding: -5+6/1-3 = -1/2
equation making: y+5 = -1/2(x-1)
rearranging: y = -1/2x +11/2
Answer:
The measure of ∠EFG is 52°
Step-by-step explanation:
Given line m is parallel to line p. m∠HEF = 39º and m∠IGF = 13º.we have to find m∠EFG.
In ΔJFG,
By angle sum property of triangle, which states that sum of all angles of triangle is 180°
m∠FJG+m∠JGF+m∠JFG=180°
⇒ 39°+13°+m∠JFG=180°
⇒ m∠JFG=180°-39°-13°=128°
As JFE is a straight line ∴ ∠JFG and ∠EFG forms linear pair
⇒ m∠JFG+m∠EFG=180°
⇒ 128°+m∠EFG=180°
⇒ m∠EFG=52°
The measure of ∠EFG is 52°
Answer:
x=28
Step-by-step explanation:
We can use similar triangles and proportions to solve this problem. Put the side of the small triangle over the same side of the larger triangle.
x 42
---------- = ----------
x+10 42+15
Simplify
x 42
---------- = ----------
x+10 57
Using cross products
57x = 42 (x+10)
Distribute
57x = 42x+420
Subtract 42x from each side
57x-42x = 42x-42x +420
15x = 420
Divide each side by 15
15x/15 = 420/15
x=28
