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Zolol [24]
3 years ago
10

A semicircle is cut out of a rectangular paperboard 24in long and 18n wide, as shown below. What is the perimeter of the paperbo

ard that remains after the semicircle is removed? (Use the value 3.14 for π , and do not round your answer. Be sure to include the correct unit in your answer.)

Mathematics
1 answer:
svet-max [94.6K]3 years ago
5 0

Answer:

Perimeter of the paperboard that remains after the semicircle is removed = 94.26 in

Step-by-step explanation:

Watch the attached figure of how the semi circle is cut out of the rectangular paperboard.

Length = 24 in

Width = 18 in

Radius of the semi circle = Half of the width of the paperboard = \frac{18}{2} = 9 in

1) Circumference of the semi circle = π*radius

= 3.14*9

= 28.26 in

2) Perimeter of the paperboard that remains after the semicircle is removed

= Top + Left + Bottom + Right Circumference of the semi circle

= 24 + 18 + 24 + 28.26

= 94.26 in


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3 years ago
John and Andrew have £3.40 between them. John has £1.20 more than Andrew. John has £u and Andrew £v
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In the given question, there are several information's of immense importance and they can be used to find the necessary answers. It is already given that John and Andrew have 3.40 pound together. It is also given that John has 1.20 pound more than Andrew. It is also assumed that John has"u" pound and Andrew has "v" pounds.
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2 years ago
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DerKrebs [107]

Answer:

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