Answer:
Perimeter of the paperboard that remains after the semicircle is removed = 94.26 in
Step-by-step explanation:
Watch the attached figure of how the semi circle is cut out of the rectangular paperboard.
Length = 24 in
Width = 18 in
Radius of the semi circle = Half of the width of the paperboard = = 9 in
1) Circumference of the semi circle = π*radius
= 3.14*9
= 28.26 in
2) Perimeter of the paperboard that remains after the semicircle is removed
= Top + Left + Bottom + Right Circumference of the semi circle
= 24 + 18 + 24 + 28.26
= 94.26 in
Answer:
A. Less than zero
Step-by-step explanation:
So If you graph the function, you'll see that it never actually crosses the y axis into the third or fourth quadrant, the quadrants where all y values become negative.
The answer A is also correct on Edge
Have a great day dude
