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2 years ago

11

Please answer ASAP

1 answer:

wel2 years ago

4 0

Answer:

Whats a you love

Step-by-step explanation:

no entiendo

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HELPPPPP MEEE PLEASE

Brut [27]

The answer is C I think

4 0

2 years ago

It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp

Semmy [17]

Answer:

$\frac{1}{5}$

Step-by-step explanation:

Using the rules of exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$ , $\frac{a^{m} }{a^{n} }$ = $a^{(m-n)}$ , $(a^m)^{n}$ = $a^{mn}$

Simplifying the product of the first 2 terms

$\frac{a^{p^2+pq} }{a^{pq+q^2} }$ × $\frac{a^{q^2+qr} }{a^{qr+r^2} }$

= $a^{p^2-q^2}$ × $a^{q^2-r^2}$

= $a^{p^2-r^2}$

Simplifying the third term

5( $(a^p+r)^{p-r}$

= 5 $a^{(p+r)(p-r)}$ = 5 $a^{(p^2-r^2)}$

Performing the division, that is

$\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} }$ ← cancel $a^{(p^2-r^2)}$ on numerator/ denominator leaves

= $\frac{1}{5}$

4 0

2 years ago

Sidana [21]

Answer:

1 $\frac{7}{20}$

Step-by-step explanation:

1. Convert the mixed number to an improper fraction to match the rest of the problem (this just makes it easier for now, the answer will still be a mixed number)

-1 $\frac{4}{5}$ becomes $\frac{9}{5}$

2. Re-write the new equation. When there is a "+" in front of a set of parentheses the expression doesn't change aside from removing the plus signs.

The new equation becomes

$\frac{9}{5} - \frac{1}{4} -\frac{1}{5}$

3. Calculate. Just work out the new expression.

The answer is $\frac{27}{20}$

4. Convert to a simplified mixed decimal.

27 goes into 20 once with seven left over, making the answer 1 $\frac{7}{20}$

8 0

2 years ago

When you are determining The probability of an event why must the probability be between 0 and 1

slega [8]

The probability of an event cannot be less than 0 because 0 means it's impossible. The probability of an event cannot be more than 1 because 1 means that it's certain that it will happen. That's why the probability must be between 0 and 1.

7 0

3 years ago

Tennis practice last for 1 hour and 35 minutes

Ghella [55]

Answer:

Where's the rest of this question??

6 0

2 years ago